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Updated on: 05 Jun 2018, 21:37
Originally posted by CAMANISHPARMAR on 05 Jun 2018, 20:25.
Last edited by CAMANISHPARMAR on 05 Jun 2018, 21:37, edited 1 time in total.
Last edited by CAMANISHPARMAR on 05 Jun 2018, 21:37, edited 1 time in total.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
57% (01:48) correct
43%
(02:24)
wrong
based on 369
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Date
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How many factors of 4800 are divisible by 12?
A) 36
B) 18
C) 15
D) 9
E) 4
A) 36
B) 18
C) 15
D) 9
E) 4
05 Jun 2018, 21:39
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tejyr
I am getting 15.
4800=12*16*25
Anyone pls explain how is it 9.
Posted from my mobile device
4800=12*16*25
Anyone pls explain how is it 9.
Posted from my mobile device
4800 could be written as 12 * 400
Now 10 is a factor of 400, so is 20, so is 400 itself, including many others.
10, 20 and 400 are not divisible by 12 but (12*10) and (12*20) are divisible by 12 because we are multiplying and dividing my 12.
Hence every factor of 400 is also of factor of 4800 and is divisible by 12 if we are multiplying each factor of 400 by 12.
To find the number of factors of 400 is a straightforward application of number of factors formula:-
(p+1)(q+1)(r+1)... [where p,q,r are exponents of each prime factor]
Therefore 400 can be written as \(2^4∗5^2\)
Therefore the number of factors of 400 are (4+1)(2+1) = 15 factors.
Therefore the no. of factors of 4800 which are divisible by 12 is 15 factors.
Your analysis is correct...good job!!
11 Jun 2018, 08:42
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Since we need to find factors of 4800 divisible by 12, We need to write 4800 as 12*k(some constant).
As 4800 = 12 * 400. We need to find factors of 400 which is also equal to factors of 4800 divisible by 12.
400 = 2^4 * 5 ^2. Therefore num of factors = (4+1)*(2+1) = 15
As 4800 = 12 * 400. We need to find factors of 400 which is also equal to factors of 4800 divisible by 12.
400 = 2^4 * 5 ^2. Therefore num of factors = (4+1)*(2+1) = 15
