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BN1989
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Bunuel
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BN1989
How many integers are there such that v<n<w?

(1) v and w are positive integers?
(2) w-v=4

How is it even possible that v<w when v-w=4?

from gmathacks

The question stem seems to ask how many integral triplets exists which are bound by v<n<w?
Whereas the intent is to ask how many integral values of n exist such that v<n<w ?

Only if we are interested in finding the no. of integral values n can take then we can get the answer
by combining 1&2 (as Bunnel stated)
But if we are interested in finding integers then obeying 1&2 we can take any natural no. as v and accordingly our w will get fixed and then we can choose any 3 no.s between w and v to get n.So infinite no. of triplets can be formed.

@Bunnel: I would be thankful if you clarify

The question should read: "How many integers N are there such that v<n<w?" There was a typo in the original post, which is now edited.
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Hi Bunuel,

Thanks for your explanation.

But why cant the answer be A.?
If we conclude condition 1 :v and w are the positive integer
We can say that Count of possible Integer Values of n will always be = w-v-1

For Example : assume w=15 , v=11
we will have count as 15-11-1 = 3
@
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Hi Bunuel,

Thanks for your explanation.

But why cant the answer be A.?
If we conclude condition 1 :v and w are the positive integer
We can say that Count of possible Integer Values of n will always be = w-v-1

For Example : assume w=15 , v=11
we will have count as 15-11-1 = 3
@

When a DS question asks about the value of some variable, then the statement(s) is sufficient ONLY if you can get the single numerical value of this variable.
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