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How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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24 Sep 2012, 05:04
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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1< 5n +5 < 25 > 4<5n<20 > .8<n<4 Four integers are possible Answer B
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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24 Sep 2012, 08:43
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Bunuel wrote: How many integers n are there such that 1< 5n +5 < 25?
(A) Five (B) Four (C) Three (D) Two (E) One
expression can be split into two equations: 1 < 5n + 5 ==> 5n > 4 ==> n > 0.8 5n + 5 < 25 ==> 5n < 20 ==> n < 4 now between 0.8 and 4(excluding) , there exist 4 integers, viz. 0, 1, 2, 3 hence B
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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10 Dec 2012, 04:23
\(1 < 5n +5 < 25\) \(1  5 < 5n + 5  5 < 25 5\) \(4 < 5n < 20\) \(4/5 < n < 4\) <===(1)=4/5 =(0)=(1)=(2)=(3)=(4)==> xaxisAnswer: B
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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11 Dec 2012, 04:14
is it correct?
5*1+5=10 5*2+5=15 5*3+5=20 5*4+5=25 >n=4



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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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24 Jun 2013, 05:06
Bunuel wrote: SOLUTION
How many integers n are there such that 1< 5n +5 < 25?
(A) Five (B) Four (C) Three (D) Two (E) One
\(1< 5n +5 < 25\) > subtract 5 from each part: \(4<5n<20\) > divide by 5 each part: \(\frac{4}{5}<n<4\). In this range there are 4 integers: 0, 1, 2, and 3.
Answer: B. why is it not 1, 0, 1, 2, 3 ?



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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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24 Jun 2013, 05:12
Rs1991 wrote: Bunuel wrote: SOLUTION
How many integers n are there such that 1< 5n +5 < 25?
(A) Five (B) Four (C) Three (D) Two (E) One
\(1< 5n +5 < 25\) > subtract 5 from each part: \(4<5n<20\) > divide by 5 each part: \(\frac{4}{5}<n<4\). In this range there are 4 integers: 0, 1, 2, and 3.
Answer: B. why is it not 1, 0, 1, 2, 3 ? Because 1 is LESS than 4/5, and n must be more than 4/5.
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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05 Sep 2013, 23:18
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A table showing values of 5n+1 for various values of n. Just need to note the constraint that 1<5n+5<25 (valid values are in green, invalid in red) and count how many valid numbers there are for n.
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Table.png [ 2.57 KiB  Viewed 13092 times ]



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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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10 Sep 2014, 09:28
Bunuel wrote: How many integers n are there such that 1< 5n +5 < 25? (A) Five (B) Four (C) Three (D) Two (E) One Practice Questions Question: 50 Page: 158 Difficulty: 600 1< 5n +5 < 25 4<5n<20 so n can take 0,1,2,3, totally 4 integers..



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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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11 Jul 2015, 00:22
Bunuel wrote: How many integers n are there such that 1< 5n +5 < 25? (A) Five (B) Four (C) Three (D) Two (E) One Practice Questions Question: 50 Page: 158 Difficulty: 600 i count only 1,2,and 3 for that reason i choose 3 integer solution: must be count from 0 so, 0,1,2,and 3 so answer: the range of integer 4



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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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08 May 2016, 14:34
The inequality given is 1 < 5n+5 < 25 it can further reduced to 4 < 5n < 20 finally 4/5 < n < 4 So can only take 5 integer values i.e. 0,1,2,3 Correct answer  B



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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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09 May 2016, 10:57
Bunuel wrote: How many integers n are there such that 1< 5n +5 < 25? (A) Five (B) Four (C) Three (D) Two (E) One Practice Questions Question: 50 Page: 158 Difficulty: 600 Solution: 1< 5n + 5 < 25 is a compound inequality. Compound inequalities often need to be manipulated, and we can use the rules of algebra that we already know, to do this. Just as with equations, whatever we do to one part of a compound inequality, we must do to all parts of the compound inequality. Let’s first isolate n within the inequality. 1< 5n + 5 < 25 We first subtract 5 from all three parts of the inequality, and we obtain: 4 < 5n < 20 Next, we divide both sides of the inequality by 5 and we get: 4/5 < n < 4 The integers that are greater than 4/5 and less than 4 are 0, 1, 2, and 3. Thus, there are 4 integers that satisfy the inequality 1 < 5n + 5 < 25. The answer is B.
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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09 Jun 2016, 07:10
Bunuel wrote: fabrizio1983 wrote: is it correct?
5*1+5=10 5*2+5=15 5*3+5=20 5*4+5=25 >n=4 No, that's not correct. n cannot be 4, since 5*4+5=25 and we are told that it must be less than 25. 1< 5n +5 < 25 n=0 > 5n +5=5; n=1 > 5n +5=10; n=2 > 5n +5=15; n=3 > 5n +5=20. Thus n can take 4 values: 0, 1, 2, or 3. Check here: howmanyintegersnaretheresuchthat15n139474.html#p1124669We are also told n is greater than 1, than how can we take 0 and 1 in the answer choice???



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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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09 Jun 2016, 07:18
Lucky_Rish wrote: Bunuel wrote: fabrizio1983 wrote: is it correct?
5*1+5=10 5*2+5=15 5*3+5=20 5*4+5=25 >n=4 No, that's not correct. n cannot be 4, since 5*4+5=25 and we are told that it must be less than 25. 1< 5n +5 < 25 n=0 > 5n +5=5; n=1 > 5n +5=10; n=2 > 5n +5=15; n=3 > 5n +5=20. Thus n can take 4 values: 0, 1, 2, or 3. Check here: howmanyintegersnaretheresuchthat15n139474.html#p1124669We are also told n is greater than 1, than how can we take 0 and 1 in the answer choice??? We are not told that n is greater than 1. We are told that \(1< 5n +5 < 25\), which is the same as \(−\frac{4}{5} < n < 4\).
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Re: How many integers n are there such that 1< 5n +5 < 25? [#permalink]
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11 Jun 2017, 22:39
Hi! To avoid getting into the trap of a ve number and fractions, we can do the following Given: \(1 < 5n+5<25\) ; Subtract throughout by 1 = \(0 < 5n+4 < 24\) > We need all positive integers which satisfies this equation. = \(4, 9, 14, 19\) are the possibilities Final answer = four
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