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Bunuel
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How many positive integers less than 1200 have no repeating digits ? 01 Nov 2023, 00:46
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

85% (hard)

Question Stats:

58% (02:54) correct 43% (03:10) wrong based on 80 sessions

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How many positive integers less than 1200 have no repeating digits ?

A. 648
B. 682
C. 794
D. 812
E. 817
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C
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Introvertuprising
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How many positive integers less than 1200 have no repeating digits ? 03 Nov 2023, 02:20
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0,1,2,3,4,5,6,7,8,9

Single digit integer with no digit repeats ={1,2,3,4,5,7,8,9} =9

Two digit integer with no digits repeats= (9*9) =81

Three digit integer =(9*9*8) =648

Four digit integer=(1*1*8*7)=56

Total 794
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Sujithz001
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How many positive integers less than 1200 have no repeating digits ? 24 Jan 2025, 21:38
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KarishmaB chetan2u Bunuel , can anyone explain this pls? I am particularly interested in knowing how to find the number of non-repeating 4-digit integers < 1200.

Thanks a lot!

Bunuel
How many positive integers less than 1200 have no repeating digits ?

A. 648
B. 682
C. 794
D. 812
E. 817
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KarishmaB
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How many positive integers less than 1200 have no repeating digits ? 24 Jan 2025, 23:09
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Bunuel
How many positive integers less than 1200 have no repeating digits ?

A. 648
B. 682
C. 794
D. 812
E. 817

Number of 1 digit numbers = 9

Number of 2 digit numbers = 9 * 9 (No 0 at the tens place and then 9 options for the units place) = 81

3 digit integers with no repeating digits = 9 * 9 * 8 = 648

Number of 4 digit numbers less than 1200: 1 0 _ _
Fill the remaining spots in 8*7 = 56 ways
Since no digit can be repeated we need to ignore the 1100 series. Our 4 digit numbers will be of the form 1023 etc only.

Total = 9 + 81 + 648 + 56 = 794

Answer (C)
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