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Re: If 2^(a + 3) = 4^(a + 2) - 48, then the value of a is [#permalink]
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ElninoEffect wrote:
Bunuel wrote:
If \(2^{a + 3} = 4^{a + 2} - 48\), then the value of a is

(A) \(\frac{-3}{2}\)
(B) -3
(C) -3
(D) 1
(E) 2



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Bunuel both options B and C are -3, I think one should have been +3. Not nitpicking just a humble observation and suggestion. :)

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Thank you! Edited.
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Re: If 2^(a + 3) = 4^(a + 2) - 48, then the value of a is [#permalink]
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The Algebra approach
4^a+2-2^a+3=2^4*3
2^2(a+2)-2^(a+3)=2^4*3
2^2a*2^4-2^a*2^3=2^4*3
2^3*2^a[2*2^a-1]=2^4*3
Equating the powers
a+3=4, a=1
Answer D
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Re: If 2^(a + 3) = 4^(a + 2) - 48, then the value of a is [#permalink]
2^a+3 = 4^a+2 - 48
4^a+2 - 2^a+3 = 48
2^2a+4 - 2^a+3 = 2^4*3
2^3*2^a(2^a-1) = 2^4*3
2^a(2^a-1) = 2*3

3 can be also be written as = (2^2-1).

Therefore,
2^a(2^a-1) = 2*(2^2-1)

a=1 or a-1=2 => a=1 (C)
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Re: If 2^(a + 3) = 4^(a + 2) - 48, then the value of a is [#permalink]
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Top Contributor
\(2^{a + 3} = 4^{a + 2} - 48\)
=> \(2^a * 2^3 = 2^{2*(a+2)} - 48\)
=> \(8 * 2^a = 2^{2a+4} - 48\)
=> \(8 * 2^a = 2^{2a}*2^4 - 48\)
=> \(8 * 2^a = 2^{2a}*16 - 8*6\)

Dividing both the sides by 8 we get
=> \(2^a = (2^a)^2*2 - 6\)

Let \(2^a\) = x
=> x = 2*\(x^2\) - 6
=> 2*\(x^2\) - x - 6 = 0
=> 2*\(x^2\) - 4x + 3x - 6 = 0
=> 2x*(x - 2) + 3*(x - 2) = 0
=> (x - 2) * (2x + 3) + 0
=> x = 2, \(\frac{-3}{2}\)

=> \(2^a\) = 2 or \(2^a\) = \(\frac{-3}{2}\)
But \(2^a\) cannot be negative
=> \(2^a\) = 2 = \(2^1\)
=> a = 1

So, Answer will be D
Hope it helps!

Watch the following video to learn the Basics of Exponents

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Re: If 2^(a + 3) = 4^(a + 2) - 48, then the value of a is [#permalink]
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