mattapraveen
If 243^x*463^y = n, where x and y are positive integers, what is the units digit of n?
(1) x + y = 7
(2) x = 4
Solution
Step 1: Analyse Question Stem
• \( 243^x*463^y = n\)
o Where x and y are positive integers.
• We need to find the unit digit of n.
o Now, the unit digit of both \(243^x\) and \(463^y\) will follow the cyclicity of 3.
o i.e. the unit digit of \(243^x\) = unit digit of \(3^x\)
o And, the unit digit of \(463^y\) = unit digit of \(3^y\)
Therefore, the unit digit of \( 243^x*463^y\) = The unit digit of \( 3^x*3^y\) = The unit digit of \(3^{x+y}\)
Thus, to find the unit digit of n we need to find the value of x + y.
Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: x+y = 7
• The unit digit of \( 243^x*463^y = n\) = The unit digit of \(3^{7}\)
• We can easily find the unit digit of \(3^{7}\) and hence the unit digit of n from this statement.
Hence, statement 1 is sufficient and we can eliminate answer Options B, C and E.
Statement 2: x = 4
• From this statement we know the value of x but we don’t know y.
• Therefore, we cannot find the unit digit of \(3^{x+y}\) and hence the unit digit of n from this statement.
Hence, statement 2 is NOT sufficient.
Thus, the correct answer is
Option A.