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Bunuel
If \(\frac{3x}{2} = y\), and \(2 - 3y = y + 2\), then x =

A. -3
B. -2
C. 0
D. 2
E. 3


2 - 3y = y + 2

4y = 0

y = 0.

Given

\(\frac{3x}{2}\)= y

\(\frac{3x}{2}\)= 0

3x = 0

x = 0.


The best answer is C.
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Bunuel
If \(\frac{3x}{2} = y\), and \(2 - 3y = y + 2\), then x =

A. -3
B. -2
C. 0
D. 2
E. 3

\(2 - 3y = y + 2\)

Or, \(4y = 0\)

So, \(y = 0\)

Thus, \(\frac{3x}{2} = 0\)

Hence, x = 0 ; Answer must be (C)
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Bunuel
If \(\frac{3x}{2} = y\), and \(2 - 3y = y + 2\), then x =

A. -3
B. -2
C. 0
D. 2
E. 3

Simplifying the second equation we have:

2 = 4y + 2

0 = 4y

0 = y

Thus,

3x/2 = 0

3x = 0

x = 0

Answer: C
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\(\frac{3x}{2} = y\)
=> 3x = 2y

2 - 3y = y + 2
=> 4y = 2 - 2 = 0
=> y =0

=> 3x = 2y = 2* 0 = 0
=> x = 0

So, Answer will be C
Hope it helps!
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