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Math Expert
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Re: If 8a = 6b and 3a = 0 then [#permalink]
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Bunuel wrote:
If 8a = 6b and 3a = 0 then

(A) a and b are equal
(B) a =6
(C) b/a = 4/3
(D) a = 6 and b = 8
(E) a/b = 3/4


given
4a=3b ;
a=0
so b=0
hence a=b=0
IMO A: :)
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Re: If 8a = 6b and 3a = 0 then [#permalink]
If 8a = 6b and 3a = 0 then

3a=0 => a=0
8a=8*0=0=6b=> b=0
a=b=0
a & b are equal

IMO A
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Re: If 8a = 6b and 3a = 0 then [#permalink]
Bunuel wrote:
If 8a = 6b and 3a = 0 then

(A) a and b are equal
(B) a =6
(C) b/a = 4/3
(D) a = 6 and b = 8
(E) a/b = 3/4

Since \(3a = 0\) ; \(a = 0\)

Now, \(8a = 6b = 0\). Thus, \(b = 0\), Answer must be (A) a and b are equal
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Re: If 8a = 6b and 3a = 0 then [#permalink]
Expert Reply
Bunuel wrote:
If 8a = 6b and 3a = 0 then

(A) a and b are equal
(B) a =6
(C) b/a = 4/3
(D) a = 6 and b = 8
(E) a/b = 3/4



Since 3a = 0, then a = 0, and 8a = 0. Thus, 0 = 6b, and b = 0.

Answer: A
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Re: If 8a = 6b and 3a = 0 then [#permalink]
A could be 1/3 also. And there is no prof that A or B has to be integer. Where am i wrong? I got answer C.

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Re: If 8a = 6b and 3a = 0 then [#permalink]
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