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Math Expert V
Joined: 02 Sep 2009
Posts: 56307
If a > 0, b > 0, and c > 0, a + 1/(b + 1/c) =  [#permalink]

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Difficulty:   5% (low)

Question Stats: 87% (01:23) correct 13% (01:41) wrong based on 86 sessions

### HideShow timer Statistics If $$a > 0$$, $$b > 0$$ , and $$c > 0$$ , $$a + \frac{1}{b + \frac{1}{c}}$$ =

A. $$\frac{a + b}{c}$$

B. $$\frac{ac + bc + 1}{c}$$

C. $$\frac{abc + b + c}{bc}$$

D. $$\frac{a + b + c}{abc + 1}$$

E. $$\frac{abc + a + c}{bc + 1}$$

_________________
VP  D
Joined: 31 Oct 2013
Posts: 1393
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
If a > 0, b > 0, and c > 0, a + 1/(b + 1/c) =  [#permalink]

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Bunuel wrote:
If $$a > 0$$, $$b > 0$$ , and $$c > 0$$ , $$a + \frac{1}{b + \frac{1}{c}}$$ =

A. $$\frac{a + b}{c}$$

B. $$\frac{ac + bc + 1}{c}$$

C. $$\frac{abc + b + c}{bc}$$

D. $$\frac{a + b + c}{abc + 1}$$

E. $$\frac{abc + a + c}{bc + 1}$$

It's better to solve this one part to part:

= $$b + \frac{1}{c}$$

=$$\frac{bc + 1}{c}$$

Then

=$$\frac{1}{(bc + 1) / c}$$

= $$\frac{c}{bc + 1}$$

last part :

= a + $$\frac{c}{bc +1}$$

=$$\frac{c + abc + a}{bc +1}$$

Manager  B
Joined: 29 Jul 2018
Posts: 114
Concentration: Finance, Statistics
GMAT 1: 620 Q45 V31 Re: If a > 0, b > 0, and c > 0, a + 1/(b + 1/c) =  [#permalink]

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assume values for a,b,c and put values of abc in options
CEO  V
Joined: 12 Sep 2015
Posts: 3857
Re: If a > 0, b > 0, and c > 0, a + 1/(b + 1/c) =  [#permalink]

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Top Contributor
Bunuel wrote:
If $$a > 0$$, $$b > 0$$ , and $$c > 0$$ , $$a + \frac{1}{b + \frac{1}{c}}$$ =

A. $$\frac{a + b}{c}$$

B. $$\frac{ac + bc + 1}{c}$$

C. $$\frac{abc + b + c}{bc}$$

D. $$\frac{a + b + c}{abc + 1}$$

E. $$\frac{abc + a + c}{bc + 1}$$

We're looking for an expression that is equivalent to the given expression.
So, if we find the value of the given expression for certain values of a, b and c, then the correct answer choice must also equal the same value for the same value of values of a, b and c.

So, let's see what happens when a = b = c = 1

Given expression: a + 1/(b + 1/c) = 1 + 1/(1 + 1/1) =
= 1 + 1/2
= 3/2

So, when a = b = c = 1, the given expression evaluates to be 3/2
So, the correct answer choice must also evaluate to be 3/2 when we plug in a = b = c = 1

A. (a + b)/c = (1 + 1)/1 = 2. No good. We need 3/2. ELIMINATE.

B. (ac + bc + 1)/c = (1 + 1 + 1)/1 = 3. No good. We need 3/2. ELIMINATE.

C. (abc + b + c)/bc = (1 + 1 + 1)/1 = 1. No good. We need 3/2. ELIMINATE.

D. (a + b + c)/(abc + 1) = (1 + 1 + 1)/(1 + 1) = 3/2. Perfect!! KEEP

E. (abc + a + c)/(bc + 1) = (1 + 1 + 1)/(1 + 1) = 3/2. Perfect!! KEEP

Okay, we have two possible answers: D or E.
So, we must test one more set of values.

Let's see what happens when a = b = 1 and c = 2
Here, the given expression: a + 1/(b + 1/c) = 1 + 1/(1 + 1/2) =
= 1 + 1/(3/2)
= 1 + 2/3
= 5/3

So, when a = b = 1 and c = 2 , the given expression evaluates to be 5/3
So, the correct answer choice must also evaluate to be 5/3 when we plug in a = b = 1 and c = 2

D. (a + b + c)/(abc + 1) = (1 + 1 + 2)/(2 + 1) = 4/3. No good. We need 5/3. ELIMINATE.

E. (abc + a + c)/(bc + 1) = (2 + 1 + 2)/(2 + 1) = 5/3. Perfect!! KEEP

Cheers,
Brent
_________________ Re: If a > 0, b > 0, and c > 0, a + 1/(b + 1/c) =   [#permalink] 30 Aug 2018, 17:25
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