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# If a wire is bent into the shape of a square, then the area enclosed

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Joined: 07 Jun 2017
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If a wire is bent into the shape of a square, then the area enclosed [#permalink]

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25 Sep 2017, 03:46
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Question Stats:

33% (00:07) correct 67% (00:17) wrong based on 3 sessions

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If a wire is bent into the shape of a square, then the area enclosed by the square is 81 cm square. When the same wire is bent into semi-circle. then the area of semi circle will be

A. 22 cm square
B . 44 cm square
C. 77 cm square
D. 81 cm square
E. 154 cm square
[Reveal] Spoiler: OA

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Last edited by pushpitkc on 25 Sep 2017, 04:06, edited 1 time in total.
Moving into appropriate forum

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Re: If a wire is bent into the shape of a square, then the area enclosed [#permalink]

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25 Sep 2017, 04:05
If the wire is bent into the shape of a square and the area is 81 $$cm^2$$
the side of the square is 9 cm. Hence, the perimeter is 4*side = 36 cm

This wire is not bent to form a semicircle which can be given by pi*r + 2*r(where r is the radius of the semicircle)

r(pi + 2) = 36 where pi = $$\frac{22}{7}$$

Therefore, r ($$\frac{36}{7}$$) = 36 => r = 7

The area of the semicircle is $$\frac{1}{2}*pi*r^2 = \frac{1}{2}*\frac{22}{7}*7*7 = 77 cm^2$$(Option C)
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Re: If a wire is bent into the shape of a square, then the area enclosed   [#permalink] 25 Sep 2017, 04:05
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