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If b=8d - c, and a=d/3, what is the average of a,b,c and d?

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If b=8d - c, and a=d/3, what is the average of a,b,c and d?  [#permalink]

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New post 01 Mar 2019, 10:05
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If b=8d - c, and a=d/3, what is the average of a,b,c and d?

A) 4a
B) 7a
C) a/7
D) 4a + 7
E) a/7 + 5
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Re: If b=8d - c, and a=d/3, what is the average of a,b,c and d?  [#permalink]

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New post 01 Mar 2019, 10:50
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Assume the value of a to be 4.
4 = d/3 => d = 12
b = 8d - c => b = 96-c
b+c = 96
Average of a,b,c,d = (a+b+c+d)/4
(4+12+96)/4 = 28..

Substitute the value of a as 4 in answer choices, we get option b as 28..

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Re: If b=8d - c, and a=d/3, what is the average of a,b,c and d?  [#permalink]

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New post 01 Mar 2019, 20:42
Have each letter in terms of d
a=d/3
b=8d-c, b+c=8d
d=d

\(\frac{\frac{d}{3}+8d+d}{4}=\frac{\frac{28d}{3}}{4}=\frac{7d}{3}\)
The options are in terms of a, and we are told that a=d/3

\(\frac{7d}{3}=7a\)

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Re: If b=8d - c, and a=d/3, what is the average of a,b,c and d?  [#permalink]

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New post 26 May 2019, 09:51
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philipssonicare wrote:
Have each letter in terms of d
a=d/3
b=8d-c, b+c=8d
d=d

\(\frac{\frac{d}{3}+8d+d}{4}=\frac{\frac{28d}{3}}{4}=\frac{7d}{3}\)
The options are in terms of a, and we are told that a=d/3

\(\frac{7d}{3}=7a\)

B


Since answer is in multiples of a , it is better to convert each letter in terms of "a". No need to convert c in any form as it will get cancelled out while we write the average formula
d= 3a
b= 8d-c = 24a-c

(a+b+c+d)/4 = (a+24a-c+c+3a)/4 = 28a/4 = 7a
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Re: If b=8d - c, and a=d/3, what is the average of a,b,c and d?   [#permalink] 26 May 2019, 09:51
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If b=8d - c, and a=d/3, what is the average of a,b,c and d?

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