It is currently 16 Mar 2018, 23:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If f(w) = (1/w) + 1$$w+8) and the function f(w) equals 1/(w-1) then a  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: ### Hide Tags Intern Joined: 08 Jun 2017 Posts: 12 If f(w) = (1/w) + 1\(w+8) and the function f(w) equals 1/(w-1) then a [#permalink] ### Show Tags 14 Oct 2017, 22:54 1 This post was BOOKMARKED 00:00 Difficulty: 15% (low) Question Stats: 83% (01:36) correct 17% (01:32) wrong based on 46 sessions ### HideShow timer Statistics If \(f(w) =\frac{1}{w} + \frac{1}{w+8}$$ and the function f(w) equals $$\frac{1}{w-1}$$, then a possible value for w could be

A) -8
B) -4
C) -2
D) -1
E) 3

(Source: Princeton Review GMAT Practice Test 6)
[Reveal] Spoiler: OA

Last edited by Bunuel on 15 Oct 2017, 01:41, edited 2 times in total.
Renamed the topic and edited the question.
PS Forum Moderator
Joined: 25 Feb 2013
Posts: 997
Location: India
GPA: 3.82
Re: If f(w) = (1/w) + 1$$w+8) and the function f(w) equals 1/(w-1) then a [#permalink] ### Show Tags 14 Oct 2017, 23:01 1 This post received KUDOS aashaybaindurgmat wrote: If f(w) =\(\frac{1}{w} + \frac{1}{w+8}$$and the function f(w) equals $$\frac{1}{w-1}$$ , then a possible value for w could be

A) -8
B) -4
C) -2
D) -1
E) 3

(Source: Princeton Review GMAT Practice Test 6)

given $$\frac{1}{w}+\frac{1}{(w+8)} = \frac{1}{(w-1)}$$

solve this to get: $$w^2-2w-8=0$$

or $$(w-4)(w+2)=0$$

so $$w=4$$ or $$-2$$

From the given options only possible value is $$-2$$

Option C

Hi aashaybaindurgmat

kindly rename the subject or ask any moderator to do it, if you are facing any difficulty.
Manager
Joined: 04 May 2014
Posts: 166
Location: India
WE: Sales (Mutual Funds and Brokerage)
Re: If f(w) = (1/w) + 1$$w+8) and the function f(w) equals 1/(w-1) then a [#permalink] ### Show Tags 18 Oct 2017, 00:03 or plugin answer choices. given 1/w+1/(w+8)=1/(w−1) let us start with c ie w=-2 -1/2+1/(-2+8)=1/(-2-1) -1/2+1/6=-1/3 -1/3=-1/3 answer c Manager Joined: 04 May 2014 Posts: 166 Location: India WE: Sales (Mutual Funds and Brokerage) Re: If f(w) = (1/w) + 1\(w+8) and the function f(w) equals 1/(w-1) then a [#permalink] ### Show Tags 18 Oct 2017, 00:09 or plugin answer choices. given \(\frac{1}{w}$$+$$\frac{1}{(w+8)}$$=$$\frac{1}{(w−1)}$$

$$\frac{-1}{2}$$+$$\frac{1}{{-2+8}}$$=$$\frac{1}{(-2-1)}$$

$$\frac{-1}{2}$$+$$\frac{1}{6}$$=$$\frac{-1}{3}$$

$$\frac{-1}{3}$$=$$\frac{-1}{3}$$ answer c
VP
Joined: 22 May 2016
Posts: 1416
If f(w) = (1/w) + 1$$w+8) and the function f(w) equals 1/(w-1) then a [#permalink] ### Show Tags 20 Oct 2017, 08:26 aashaybaindurgmat wrote: If \(f(w) =\frac{1}{w} + \frac{1}{w+8}$$ and the function f(w) equals $$\frac{1}{w-1}$$, then a possible value for w could be

A) -8
B) -4
C) -2
D) -1
E) 3

(Source: Princeton Review GMAT Practice Test 6)

This math just looks time-consuming. It is not. Numbers are easy.*

$$f(w) =\frac{1}{w} + \frac{1}{w+8}$$

And $$f(w) = \frac{1}{w-1}$$. Set them equal.

$$\frac{1}{w-1} = \frac{1}{w} + \frac{1}{w+8}$$*

$$\frac{1}{w-1} = \frac{(w+8)+w}{w(w+8)}$$

$$\frac{1}{(w-1)} = \frac{2w+8}{w^2+8w}$$

$$(2w+8)(w-1) = w^2 + 8w$$

$$2w^2 - 2w + 8w - 8 = w^2 + 8w$$

$$w^2 - 2w - 8 = 0$$

$$(w - 4)(w + 2) = 0$$

$$w = 4$$ or $$w = -2$$

First option is not a choice. w = -2

*Use $$\frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab}$$
_________________

At the still point, there the dance is. -- T.S. Eliot
Formerly genxer123

If f(w) = (1/w) + 1\(w+8) and the function f(w) equals 1/(w-1) then a   [#permalink] 20 Oct 2017, 08:26
Display posts from previous: Sort by