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# If N is a 3-digit positive integer and when N is divided by

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Current Student
Joined: 11 May 2008
Posts: 555

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If N is a 3-digit positive integer and when N is divided by [#permalink]

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01 Aug 2008, 03:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

. If N is a 3-digit positive integer and when N is divided by 15, the remainder is 2, N=?
(1) When N is divided by 24, the remainder is 2.
(2) When N is divided by 21, the remainder is 2.
A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient

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Current Student
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01 Aug 2008, 04:47
nikhil... pls explain....if there are'nt any previously

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Manager
Joined: 14 Jan 2006
Posts: 96

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Schools: HKUST

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01 Aug 2008, 05:08
arjtryarjtry wrote:
. If N is a 3-digit positive integer and when N is divided by 15, the remainder is 2, N=?
(1) When N is divided by 24, the remainder is 2.
(2) When N is divided by 21, the remainder is 2.
A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient

we need to find N
let N=15k1 + 2

1.) N = 24k2 + 2
since both the remainders are same, we need to take the LCM of 15 and 24. the equation becomes: 120k12+2...N can be 122,242, etc.

2.)N = 21k3 + 2
using LCM, N = 105k13 + 2 ...again, N can be 107, 212, etc.

Using 1 and 2, N = 840k123 + 2...N is 842

Therefore, C

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Senior Manager
Joined: 16 Jul 2008
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01 Aug 2008, 05:13
I see, but no freaking way I can solve this in two minutes or less...
_________________

http://applicant.wordpress.com/

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Current Student
Joined: 11 May 2008
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01 Aug 2008, 05:15
thanks... but if remainders are different, then how do u get the resulting general form...
say A=15k+2
A=12K+3.
SO how do u integrate the two?

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Re: 3 digit no.   [#permalink] 01 Aug 2008, 05:15
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