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24 Dec 2020, 04:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
98% (00:50) correct
2%
(01:16)
wrong
based on 128
sessions
History
Date
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Not Attempted Yet
If \(r = –2\), then \(r^4 + 2r^3 + 3r^2 + r =\) ?
(A) –8
(B) –4
(C) 0
(D) 6
(E) 10
(A) –8
(B) –4
(C) 0
(D) 6
(E) 10
24 Dec 2020, 04:38
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Rearranging the terms slightly, we get \(r^4 + 3r^2 + 2r^3 + r\)
Factorising: \(r^2(r^2 + 3) + r(2r^2 + 1)\)
\(r^2 = -2^2 = 4\)
Substituting, we get 4(4 + 3) - 2(8 + 1) = 28 - 18 = 10
Option E
Arun Kumar
Factorising: \(r^2(r^2 + 3) + r(2r^2 + 1)\)
\(r^2 = -2^2 = 4\)
Substituting, we get 4(4 + 3) - 2(8 + 1) = 28 - 18 = 10
Option E
Arun Kumar
24 Dec 2020, 04:42
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IMO E
-2^4 + 2(-2)^3 + 3(-2)^2 + (-2)
Simplifying this we get = 10
-2^4 + 2(-2)^3 + 3(-2)^2 + (-2)
Simplifying this we get = 10
