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29 Oct 2017, 01:32
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (00:37) correct
10%
(00:42)
wrong
based on 130
sessions
History
Date
Time
Result
Not Attempted Yet
If x^2 + 2x – 8 = 0, then x is either –4 or
(A) –2
(B) –1
(C) 0
(D) 2
(E) 8
(A) –2
(B) –1
(C) 0
(D) 2
(E) 8
29 Oct 2017, 08:09
Kudos
Bookmarks
Bunuel
\(x^2 + 2x – 8 = 0\)
Or, \(x^2 + 4x - 2x - 8 = 0\)
Or, \(x(x + 4 ) -2 (x + 4) = 0\)
Or, x = 2 and x = -4
Thus, answer will be (D) 2
