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If (x^2 + 6x + 9) + 6(x+3) + 9 = 0, then x=

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If (x^2 + 6x + 9) + 6(x+3) + 9 = 0, then x=  [#permalink]

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New post 02 Nov 2018, 01:26
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

81% (01:25) correct 19% (01:04) wrong based on 26 sessions

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If \((x^2 + 6x + 9) + 6(x+3) + 9 = 0\), then x=

(A) -6
(B) -3
(C) 0
(D) 3
(E) 6

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Re: If (x^2 + 6x + 9) + 6(x+3) + 9 = 0, then x=  [#permalink]

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New post 02 Nov 2018, 01:49
1
On careful observation we notice that the expression inside the first paranthesis is square of \(x+3\)
\((x^2 + 6x + 9) + 6(x+3) + 9 = 0\)

Hence we can denote x+3 by a new variable t.

Expression becomes...
\(t^2+6t+9=0\)
\((t+3)^2=0\)
\(t=-3\)
Substitute back to get original variable
\(x+3=-3\)
\(x = -6\)

Hence Option (A) is our choice.

Best,
Gladi

pushpitkc wrote:
If \((x^2 + 6x + 9) + 6(x+3) + 9 = 0\), then x=

(A) -6
(B) -3
(C) 0
(D) 3
(E) 6

_________________

Regards,
Gladi



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GMAT Club Bot
Re: If (x^2 + 6x + 9) + 6(x+3) + 9 = 0, then x= &nbs [#permalink] 02 Nov 2018, 01:49
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If (x^2 + 6x + 9) + 6(x+3) + 9 = 0, then x=

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