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If x is a positive integer, then the least value of x for which x! is

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If x is a positive integer, then the least value of x for which x! is  [#permalink]

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New post Updated on: 08 Jan 2015, 08:23
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If x is a positive integer, then the least value of x for which x! is divisible by 1000 is?

A. 5
B. 9
C, 12
D. 15
E. 30

Can someone please explain intuitively what the question is asking?

Originally posted by iNumbv on 08 Jan 2015, 08:20.
Last edited by Bunuel on 08 Jan 2015, 08:23, edited 1 time in total.
Renamed the topic and edited the question.
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Re: If x is a positive integer, then the least value of x for which x! is  [#permalink]

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New post 08 Jan 2015, 08:28
Going by logic, x! must contain 1000 or its factors in it

1000= 5*2*5*2*5*2

Always in such type of questions '5' will be the limiting number. So we need three "5" in x!

And smallest factorial will be 15!, it contains 5, 10, 15 .

:-D


iNumbv wrote:
If x is a positive integer, then the least value of x for which x! is divisible by 1000 is?

A. 5
B. 9
C, 12
D. 15
E. 30

Can someone please explain intuitively what the question is asking?

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Joined: 13 Jun 2013
Posts: 276
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Re: If x is a positive integer, then the least value of x for which x! is  [#permalink]

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New post 08 Jan 2015, 08:32
iNumbv wrote:
If x is a positive integer, then the least value of x for which x! is divisible by 1000 is?

A. 5
B. 9
C, 12
D. 15
E. 30

Can someone please explain intuitively what the question is asking?



1000= 2^3*5^3

therefore x! must have 5^3 in it. so, out of the given options only 15 and 30 remains. Also, since the question talks about the least value of x. therefore x must be 15.
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Re: If x is a positive integer, then the least value of x for which x! is  [#permalink]

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New post 08 Jan 2015, 08:32
2
1
iNumbv wrote:
If x is a positive integer, then the least value of x for which x! is divisible by 1000 is?

A. 5
B. 9
C, 12
D. 15
E. 30

Can someone please explain intuitively what the question is asking?


In order x! to be divisible by 1,000, it should have at least 3 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it: 2*5 = 10. So, we need 10 to be in x! at least in power of 3.

5! = 120 has 1 trailing zeros.
10! will have 2 trailing zeros.
15! will have 3 trailing zeros.

Answer: D.
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Re: If x is a positive integer, then the least value of x for which x! is  [#permalink]

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New post 08 Jan 2015, 08:33
Bunuel wrote:
iNumbv wrote:
If x is a positive integer, then the least value of x for which x! is divisible by 1000 is?

A. 5
B. 9
C, 12
D. 15
E. 30

Can someone please explain intuitively what the question is asking?


In order x! to be divisible by 1,000, it should have at least 3 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it: 2*5 = 10. So, we need 10 to be in x! at least in power of 3.

5! = 120 has 1 trailing zeros.
10! will have 2 trailing zeros.
15! will have 3 trailing zeros.

Answer: D.


For similiar questions check Trailing Zeros Questions and Power of a number in a factorial questions in our Special Questions Directory.



Hope this helps.
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New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: If x is a positive integer, then the least value of x for which x! is  [#permalink]

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New post 05 Apr 2018, 08:49
X! will be divisible by 1000 only if it has 3 trailing zeros. 1 trailing zero means there is at least one 2 and one 5 in the product. Concept - https://gmatclub.com/forum/everything-a ... 85592.html

Now, 5 has one trailing zero, 10 has two trailing zeros and 15 has three trailing zeros. So the answer is D.
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Re: If x is a positive integer, then the least value of x for which x! is &nbs [#permalink] 05 Apr 2018, 08:49
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