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If x is equal to either 2/3 or 3/8 and y is equal to either

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If x is equal to either 2/3 or 3/8 and y is equal to either [#permalink]

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New post 10 Sep 2008, 10:07
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x is equal to either 2/3 or 3/8 and y is equal to either 1/2 of x or 1/3 of x, what is the value of y?

1. x-y=y
2. x+y=1

a) 1 is sufficient
b) 2 is sufficient
c) 1 & 2 together are sufficient
d) Either 1 or 2 is sufficient
e) Neither 1 nor 2 is sufficient

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Re: Math Question - Data Sufficiency [#permalink]

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New post 10 Sep 2008, 10:20
HVD1975 wrote:
If x is equal to either 2/3 or 3/8 and y is equal to either 1/2 of x or 1/3 of x, what is the value of y?

1. x-y=y
2. x+y=1


//B//

x = 2/3 or 3/8
if x = 2/3, y = 1/2 (2/3) or 1/3 (2/3)
if x = 3/8, y = 1/2 (3/8) or 1/3 (3/8)

1: x - y = y
x = 2y

y could be either 1/3 or 2/9. so nsf.

2: x+y = 1
only possible if x= 2/3 and y = 1/2 (2/3)
x + y = 2/3 + 1/3 = 1

so B.
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Re: Math Question - Data Sufficiency [#permalink]

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New post 10 Sep 2008, 10:26
C for me.

From 1, y could be 1/3 or 3/16.
From 2, y could be 1/3 or 5/8.

Combining the two, y will be 1/3.

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Re: Math Question - Data Sufficiency [#permalink]

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New post 10 Sep 2008, 10:37
HVD1975 wrote:
If x is equal to either 2/3 or 3/8 and y is equal to either 1/2 of x or 1/3 of x, what is the value of y?

1. x-y=y
2. x+y=1

a) 1 is sufficient
b) 2 is sufficient
c) 1 & 2 together are sufficient
d) Either 1 or 2 is sufficient
e) Neither 1 nor 2 is sufficient


B

x+y=1 is possible only when x=2/3 and y=1/3

only one solution.
sufficient
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Re: Math Question - Data Sufficiency [#permalink]

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New post 10 Sep 2008, 13:30
B

1. x-y = y
x = 2/3 or 3/8
y = x/2 or x/3

lets substituate the value of y in x

for y=x/2
x-(x/2) = x/2 = y ....true

for y=x/3
x-(x/3) = 2x/3 not equal to y...false.

so now we know for the first equation, y=x/2, since x can be 2/3 or 3/8, we cannot get a single value for y

2. x+y = 1
x = 2/3 or 3/8
y = x/2 or x/3

lets substituate the value of y in x

for y=x/2
x+(x/2) = 1
3x/2 = 1 => x = 2/3(it one of the given values of x)
for x=2/3 , subsitute x for y => y = (2/3)/2 = 1/3

for y=x/3
x+(x/3) = 1
4x/3 = 1 => x = 3/4(is not the given value of x...so invalid case)

From 2, we got x=2/3 and y = 1/3.

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Re: Math Question - Data Sufficiency   [#permalink] 10 Sep 2008, 13:30
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