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If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:00
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61% (01:26) correct 39% (01:23) wrong based on 298 sessions
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If \(x = y\), \(x + y = ?\) (1) \(x  y = 4\) (2) \(\frac{x}{y} = 1\)
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If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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Updated on: 13 Jul 2019, 09:30
Given: x=y Question: x+y=? Statement 1: x−y=4 Since x=y => x = y or x=y xy=4 x<>y => x=y x=2 & y=2 x+y=0 SUFFICIENT Statement 2: x/y=−1 x=y x+y=0 SUFFICIENT IMO D
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Originally posted by Kinshook on 12 Jul 2019, 08:16.
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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:13
A alone is sufficient because the numbers have to be 2 and 2. B is not sufficient because it could be 1/1 or 1/1. A is the answer.
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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:14
stat A... is just sufficient since as per that x,y takes diff values except for (2,2) for given conditions



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:20
IMO Answer is A: given x = y, x=y or x=y
from 1: if x=y, then xy should be 0, but xy = 4, so x nad y have opp signs. so, x=y we have 2 equations, x+y=0 and xy=4, these can be solved to find x and y, sufficient
from 2: all we know is x and y have opp signs, so not suff
so A is the answer



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:20
If x=y, x+y=?
Given: x=y => x = y or x = y
(1) x−y=4 > correct: xy = 0, so xy != 0 i.e x != y, so x = y => x+y = 0
(2) x/y=−1 > correct: x = y, so x+y =0
So, the answer: D



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If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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Updated on: 12 Jul 2019, 20:04
If x=y, x+y=? this implies x = +/y that is x+y=0 or xy=0 (1) x−y=4 therefore x+y=0 (2) x/y=−1 x=y, therefore x+y=0 Both statements individually imply that X + y = 0. Option D Posted from my mobile device
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Originally posted by prashanths on 12 Jul 2019, 08:22.
Last edited by prashanths on 12 Jul 2019, 20:04, edited 1 time in total.



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:25
If x=y, x+y=?
(1) x−y=4
(2) x/y=−1
we are given x = y which means x = y or x = y
1. x  y =4 hence x = y + 4 now from above equation if we substitute here. X = Y will not satisfy x = y + 4. So only x = y can be substituted in x = y + 4, which will mean x = 2 and y = 2 hence x + y = 0  Sufficient
2. x/y = 1, simplifying the equation we will get x = y and hence x + y = 0.  Sufficient
Answer  D



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:26
If x = y, then either x = y or x = y Considering statement (1) alone: x  y = 4 The only possible values are x = 2 and y = 2 SUFFICIENT Considering statement (2) alone: x = y SUFFICIENT The answer is (D).
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If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:30
Statement 1 If x and y are same. Only way is 2  (2) = 4 Statement 2 2 combinations X negative y postive X positive y negative Either ways x+y will be 0 Thus answer is D Posted from my mobile device
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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:32
Quote: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1 If x=y, then they have the same value, and either the same sign or alternate signs; (1) x  y = 4: then x=2 y=2, or x=2 y=2, in both cases x+y=0, sufficient. (2) x/y = 1: then, they have alternate signs, and their sum will always be 0, sufficient. Answer (D).



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:33
A
From the given equation, x = y and x = y.
From st 1: x = y +4, we cant solve this equation with x = y, so we get only one solution, i.e. x = 2 and y = 2. Sufficient From st 2: x = y, we will get infinite solutions. Not Sufficient.



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:35
If x=y , x+y=?
(1) x−y=4
If xy=4 then x=y+4 y+4=y the only possible solution is y=2 x=2+4=2 x+y=22=0 Sufficient
(2) x/y=1
This statement tells us that x and y are the same numbers but with different sings. thus their sum should be equal to 0 Sufficient.
IMO D



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:36
Given x^2=y^2; x^2y^2 =0; (xy)(x+y)=01) xy=4 Sufficient as 4(x+y)=0 gives x+y=0 2)x=y Sufficient as y+y=0 IMO D
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If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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Updated on: 13 Jul 2019, 03:48
given x=y, so x= y possible when either of them is same or opposite sign viz. x=y or x=y orx=y #1 x−y=4 from given condition its only possible when x=2 and y=2 sufficient to say that x+y=0 #2 x=y so x+y=0 sufficient IMO D
If x=y, x+y=?
(1) x−y=4
(2) x/y=−1
Originally posted by Archit3110 on 12 Jul 2019, 08:40.
Last edited by Archit3110 on 13 Jul 2019, 03:48, edited 1 time in total.



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:40
Answer C : Both statements are sufficient
Suppose X =2, Y =2 so x =2 and y= 2 which gives xy =2+ (2) = 4 , so x+y = 0 , sufficient
again consider same x/y =1, 1 can only result if both integers are same and one is negative. In this case x+y = 0 So sufficient
Both are individually sufficient



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:51
From the first statement we know that sign of x and y can't be same. Then if we use y=x and substitute it in the equation we will get value of x and y. Thus first statement is sufficient.
Second statement only tells us about the sign and not the magnitude and thus we cannot find the value of x+y
Answer is A
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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:52
Given x=y Hence there are two cases: 1) y=x and 2) y=x Question stem: x+y=? St1: xy=4 When y=x then xy=0 (So this case is not satisfied) When y=x then xy=2x=4 or x=2 so y=2. Therefore x+y=0 Sufficient. St2: x/y=1 or x=y Now x+y=y+y=0 Sufficient. Ans. (D)
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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:52
modX = modY x=y x=y x=y x=y
From A since XY =4, X and y cannot be of same sign as if they are of same sign will xy=0 possibility x=y x=y
Adding X+y=0 in both the possibilities hence we can conclude it from A.
From B x/y = 1 x=y so x+y=0
both 1st and 2nd satements can independently answer. So D is the answer.



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Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:56
IMO D
Given, x=y => squaring both sides, x^2=y^2 => x^2y^2=0 => (x+y)(xy)=0 => Either x+y=0 or xy=0
From (1) x−y=4 (i.e. not 0), hence x+y=0 Sufficient
From (2) x/y=−1 => x=y => x+y=0 Sufficient




Re: If x = y, x + y = ? (1) x  y = 4 (2) x/y = 1
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12 Jul 2019, 08:56



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