If y≠0 and y≠-1, which is greater, x/y or x/(y+1)?

(1) x≠0

(2) x > y

Sol:

(1) x!=0 doesn't tell us anything.

x=10

y=1

\(\frac{x}{y}=10\)

\(\frac{x}{y+1}=\frac{10}{2}=5\)

\(\frac{x}{y}>\frac{x}{y+1}\)

x=-10

y=-2

\(\frac{x}{y}=\frac{-10}{-2}=5\)

\(\frac{x}{y+1}=\frac{-10}{-1}=10\)

\(\frac{x}{y}<\frac{x}{y+1}\)

(2) It tells us that x and y have same sign

x > y

x/y > 1 (same sign)

Use sample set from statement 1.

Not sufficient.

Combining both;

Use sample set from statement 1.

Not Sufficient.

Ans: "E"

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~fluke

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