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If Y < X and XM < YM, what must be true?

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If Y < X and XM < YM, what must be true? [#permalink]

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New post 07 Jul 2016, 05:59
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Re: If Y < X and XM < YM, what must be true? [#permalink]

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New post 07 Jul 2016, 07:41
Bunuel wrote:
If Y < X and XM < YM, what must be true?

A. M < X.
B. M < Y.
C. X < 0.
D. M < 0.
E. Y < 0.

Case 1
M>0
then X<Y
Case 2
M<0
X>Y
ATQ Y<X
we have case 2
so M<0
Ans D
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Re: If Y < X and XM < YM, what must be true? [#permalink]

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New post 08 Jul 2016, 10:40
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Bunuel wrote:
If Y < X and XM < YM, what must be true?

A. M < X.
B. M < Y.
C. X < 0.
D. M < 0.
E. Y < 0.


X>Y, bus as soon as M is multiplied to both sides inequality sign changes.

This is only possible when -ve is multiplied on both sides. That means M is -ve

D is the answer
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Re: If Y < X and XM < YM, what must be true? [#permalink]

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New post 10 Jul 2016, 02:00
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Since M reverses the equality so it must be -ve. so D
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Re: If Y < X and XM < YM, what must be true? [#permalink]

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New post 29 Jan 2018, 10:54
Bunuel wrote:
If Y < X and XM < YM, what must be true?

A. M < X.
B. M < Y.
C. X < 0.
D. M < 0.
E. Y < 0.


We see that when X and Y are multiplied by M, the inequality is switched. That means M must be less than zero.

For example, if X = 2, and Y = -3, and M = -1, we have:

-2 > -3

(2)(-1) < (-3)(-1)

2 < 3

Answer: D
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Re: If Y < X and XM < YM, what must be true?   [#permalink] 29 Jan 2018, 10:54
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