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why can it not be : P(1 red balloon) + P(2 red balloons) + p(3 red balloons)?

that would be 1/6 * 5/6 * 5/6 + 1/6 * 1/6 * 5/6 + 1/6 * 1/6 * 1/6 ... can someone explain please? Thanks in advance
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Bunuel it is not written whether it is with replacement or without replacements ? Just saying randomly selected is sufficient ?? Please give your valuable opinion. Thanks in advance!!

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Bunuel it is not written whether it is with replacement or without replacements ? Just saying randomly selected is sufficient ?? Please give your valuable opinion. Thanks in advance!!

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The stem should have said "with replacement". Edited. Thank you!
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why can it not be : P(1 red balloon) + P(2 red balloons) + p(3 red balloons)?

that would be 1/6 * 5/6 * 5/6 + 1/6 * 1/6 * 5/6 + 1/6 * 1/6 * 1/6 ... can someone explain please? Thanks in advance

You need to add permutations also since it will affect the total possible combinations.

Even if only one ball is red while picking , 1R 1W 1W is different than 1W 1R 1W.

(1/6 * 5/6 * 5/6) * 3
+ (1/6 * 1/6 * 5/6 ) * 3
+ (1/6 * 1/6 * 1/6) = 91/216
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Bunuel
In a bag of balloons, the ratio of red balloons to other colors is 1:5, if 3 balloons are selected from the bag at random with replacement, what is the probability that at least one balloon is red?

(A) 91/216
(B) 25/72
(C) 71/216
(D) 61/216
(E) 59/216

Probability of selecting a Red balloon is 1/6 and that of selecting a non red balloon is 5/6.
Since the selection happens with replacement, this probability does not change no matter how many actual balloons there are.

Probability (at least 1 red balloon in 3 picks) = 1 - Probability (No Red balloon in 3 picks)

Probability (No Red balloon in 3 picks) = (5/6)*(5/6)*5/6)

Probability (at least 1 red balloon) = 1 - (5/6)*(5/6)*5/6) = 91/216

Answer (A)
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