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Intern
Joined: 24 Nov 2003
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Location: Champaign

In a certain pond, 50 fish were caught, tagged, and returned
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Updated on: 28 Oct 2013, 15:00
Question Stats:
77% (01:09) correct 23% (01:08) wrong based on 350 sessions
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In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond? (A) 400 (B) 625 (C) 1,250 (D) 2,500 (E) 10,000 OPEN DISCUSSION OF THIS QUESTION IS HERE: inacertainpond50fishwerecaughttaggedandreturned119175.html
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Originally posted by maverick_ucdc on 28 Nov 2003, 05:49.
Last edited by Bunuel on 28 Oct 2013, 15:00, edited 1 time in total.
Renamed the topic, edited the question and added the OA.



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Joined: 14 Oct 2003
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Location: On Vacation at My Crawford, Texas Ranch

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Updated on: 28 Nov 2003, 06:57
What's there to disagree with?
This is a rather straight forward ratio problem.
1. 50 fish tagged
2. 2 out of the 50 fish caught were tagged thus 2/50
2/50=50/x
thus, x=1250
Think of the analogy: 2 fish is to 50 Fish as 50 fish is to ...?
You've tagged 50 fish and you need to find what that comprises as a percentage of the total fish population  we have that information with the ratio of the second catch.
Originally posted by Titleist on 28 Nov 2003, 06:49.
Last edited by Titleist on 28 Nov 2003, 06:57, edited 1 time in total.



Intern
Joined: 24 Nov 2003
Posts: 29
Location: Champaign

Got it  thanks  i was trying to use too much of (FLAWED) logic.



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Re: In a certain pond, 50 fish were caught, tagged, and returned
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28 Oct 2013, 15:00



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Re: In a certain pond, 50 fish were caught, tagged, and returned
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04 Feb 2019, 10:59
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Re: In a certain pond, 50 fish were caught, tagged, and returned
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04 Feb 2019, 10:59






