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08 Nov 2021, 07:45
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
82% (02:13) correct
18%
(02:57)
wrong
based on 201
sessions
History
Date
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Not Attempted Yet
In how many ways can 10 different paintings be distributed between two collectors – Dave and Mona – if Dave should get either three paintings or five paintings? (All paintings should be given away).
A) 120
B) 252
C) 372
D) 1092
E) 2100
A) 120
B) 252
C) 372
D) 1092
E) 2100
Archit3110
Major Poster
08 Nov 2021, 07:53
Kudos
Bookmarks
total paintings 10
For Dave to get 3 paintings 10c3 ways and 5 paintings 10c5
total ways would be 10c3+10c5 ; 120+ 252 ; 372 ways
option C
For Dave to get 3 paintings 10c3 ways and 5 paintings 10c5
total ways would be 10c3+10c5 ; 120+ 252 ; 372 ways
option C
Bunuel
08 Nov 2021, 07:54
Kudos
Bookmarks
We're either choosing 3 paintings from the ten to give to Dave, or we're choosing 5 paintings from the 10 to give to Dave. The order of the paintings doesn't matter, so the answer is 10C5 + 10C3 = 252 + 120 = 372.
