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In the equation above, k is a constant. If y = 17 when x = 2

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In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

(A) 34
(B) 31
(C) 14
(D) 11
(E) 7

Practice Questions
Question: 54
Page: 159
Difficulty: 600


GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 01 Oct 2012, 04:08
SOLUTION

y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?


(A) 34
(B) 31
(C) 14
(D) 11
(E) 7

Since if \(y = 17\) when \(x = 2\), then \(17 = 2k + 3\) --> \(k=7\).

Thus, \(y = 7x + 3\). When \(x=4\), \(y = 7*4 + 3=31\).

Answer: B.
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 01 Oct 2012, 04:17
1
\(y = kx + 3\) is the equation of the slope but in this context the question is different

\(y = K * 2 + 3\)to have y = 17 then K must be 7

\(17 = 7*2 + 3\)

\(y = 7*4 + 3\) ---> \(y = 31\)

B must be the answer. Sub 600

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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 01 Oct 2012, 18:53
Answer is B.
Same explanation as Carcass's
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 03 Oct 2012, 23:43
Answer is B (=31)

Explanation is same as provided by Carcass above.
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 04 Oct 2012, 01:47
2
1) Put y =17 and x=2 and solve for K
2) Knowing k=7 from above and x=4 solve for Y ------> Y=31

Answer is B
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 04 Oct 2012, 13:14
SOLUTION

y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?


(A) 34
(B) 31
(C) 14
(D) 11
(E) 7

Since if \(y = 17\) when \(x = 2\), then \(17 = 2k + 3\) --> \(k=7\).

Thus, \(y = 7x + 3\). When \(x=4\), \(y = 7*4 + 3=31\).

Answer: B.

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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 05 Oct 2012, 02:23
1 st step : solve given eqn for K by putting values of x and y. u get k=7
snd step : now put banck value of k=7 and x=4 in given eqn and solve for y.
you get y=31

so Y=31 answer
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 10 Dec 2012, 03:47
y = kx + 3
17 = k(2) + 3 --> 14 = 2k --> k=7

y = (7)(4) + 3 --> y = 31

Answer: B
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 10 Sep 2014, 18:16
Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

(A) 34
(B) 31
(C) 14
(D) 11
(E) 7

Practice Questions
Question: 54
Page: 159
Difficulty: 600


GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
1. Please provide your solutions to the questions;
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!



given
y=kx+3

y=17 ; x=2

k = 4.

y=? if x = 7

y=31
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 30 May 2016, 04:28
Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

(A) 34
(B) 31
(C) 14
(D) 11
(E) 7


We are given the equation y = kx + 3, where k is a constant.

We are also given that y = 17 when x = 2, so we can plug these values into the equation to first determine a value for k.
y = kx + 3

17 = 2k + 3

14 = 2k

k = 7

We now can determine the value of y when x = 4:

y = kx + 3

y = (7)(4) + 3

y = 28 + 3

y = 31

The answer is B.
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 30 May 2016, 05:11
Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

(A) 34
(B) 31
(C) 14
(D) 11
(E) 7



Given: y = kx + 3
Putting values of y and x.

17 = 2k+3; 2k = 14; k = 7.

Once k is known, I can calculate y for any value of x.

y = kx + 3
= {(7) * 4} +3
= 31

B is the answer
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 20 Jun 2016, 14:47
The approach is right as seen above.
But I doubt that this question is a 600 difficulty question.
Maybe sub-600 more obviously.
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 10 Aug 2017, 11:10
y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

(A) 34
(B) 31
(C) 14
(D) 11
(E) 7

May as well to use such approach:
If y = 17 when x = 2 -> 17 = 2k+3
When x = 4, y = 4k+3 = 2*(2k+3)-3=2*17-3=31
The answer is B.
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 20 Aug 2017, 15:10
My approach inspired by a video I saw on GMATPrepNow was pretty quick.
I saw the y intercept in the equation "y = kx + 3" = 3 which implies coordinate (0,3)
Then the question gave away another coordinate (2,17) which shows that there was a 14 point rise in y with a 2 point run in x
Hence, another 2 point run in x makes x=4 and y=17+14=31
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 20 Aug 2018, 00:19
4
y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

17=2K+3
K=14/2=7

y=7*4+3=31
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 20 Aug 2018, 06:06
Bunuel wrote:
y = kx + 3

In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

(A) 34
(B) 31
(C) 14
(D) 11
(E) 7


\(y = kx + 3\)

Substitute \(y = 17\) & \(x = 2\) in the above equation

Or, \(17 = k*2 + 3\)

Or, \(2k = 14\)

Or, \(k = 7\)

Quote:
what is the value of y when x = 4 ?


Substitute x = 4 in the equation \(y = kx + 3\)

Or, \(y = 7*4 + 3\)

So, \(y = 31\), Answer must be (B)
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Re: In the equation above, k is a constant. If y = 17 when x = 2  [#permalink]

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New post 20 Aug 2018, 08:03
\(y=kx+3\)
\(17=2k+3\)
\(k=7\)
now
\(y=4*7+3\)
\(y=31\)
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Re: In the equation above, k is a constant. If y = 17 when x = 2 &nbs [#permalink] 20 Aug 2018, 08:03
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