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In the equation above, k is a constant. If y = 17 when x = 2
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01 Oct 2012, 04:07
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Re: In the equation above, k is a constant. If y = 17 when x = 2
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01 Oct 2012, 04:08



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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Re: In the equation above, k is a constant. If y = 17 when x = 2
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01 Oct 2012, 18:53
Answer is B. Same explanation as Carcass's
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Re: In the equation above, k is a constant. If y = 17 when x = 2
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03 Oct 2012, 23:43
Answer is B (=31)
Explanation is same as provided by Carcass above.



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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04 Oct 2012, 01:47
1) Put y =17 and x=2 and solve for K 2) Knowing k=7 from above and x=4 solve for Y > Y=31
Answer is B



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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04 Oct 2012, 13:14



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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05 Oct 2012, 02:23
1 st step : solve given eqn for K by putting values of x and y. u get k=7 snd step : now put banck value of k=7 and x=4 in given eqn and solve for y. you get y=31
so Y=31 answer



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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10 Dec 2012, 03:47
y = kx + 317 = k(2) + 3 > 14 = 2k > k=7y = (7)(4) + 3 > y = 31Answer: B
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Re: In the equation above, k is a constant. If y = 17 when x = 2
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10 Sep 2014, 18:16
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions Projecty = kx + 3In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ? (A) 34 (B) 31 (C) 14 (D) 11 (E) 7 Practice Questions Question: 54 Page: 159 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you! given y=kx+3 y=17 ; x=2 k = 4. y=? if x = 7 y=31



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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30 May 2016, 04:28
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions Projecty = kx + 3In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ? (A) 34 (B) 31 (C) 14 (D) 11 (E) 7 We are given the equation y = kx + 3, where k is a constant. We are also given that y = 17 when x = 2, so we can plug these values into the equation to first determine a value for k. y = kx + 3 17 = 2k + 3 14 = 2k k = 7 We now can determine the value of y when x = 4: y = kx + 3 y = (7)(4) + 3 y = 28 + 3 y = 31 The answer is B.
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Re: In the equation above, k is a constant. If y = 17 when x = 2
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30 May 2016, 05:11
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions Projecty = kx + 3In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ? (A) 34 (B) 31 (C) 14 (D) 11 (E) 7 Given: y = kx + 3 Putting values of y and x. 17 = 2k+3; 2k = 14; k = 7. Once k is known, I can calculate y for any value of x. y = kx + 3 = {(7) * 4} +3 = 31 B is the answer



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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20 Jun 2016, 14:47
The approach is right as seen above. But I doubt that this question is a 600 difficulty question. Maybe sub600 more obviously.
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Re: In the equation above, k is a constant. If y = 17 when x = 2
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10 Aug 2017, 11:10
y = kx + 3
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34 (B) 31 (C) 14 (D) 11 (E) 7
May as well to use such approach: If y = 17 when x = 2 > 17 = 2k+3 When x = 4, y = 4k+3 = 2*(2k+3)3=2*173=31 The answer is B.



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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20 Aug 2017, 15:10
My approach inspired by a video I saw on GMATPrepNow was pretty quick. I saw the y intercept in the equation "y = kx + 3" = 3 which implies coordinate (0,3) Then the question gave away another coordinate (2,17) which shows that there was a 14 point rise in y with a 2 point run in x Hence, another 2 point run in x makes x=4 and y=17+14=31



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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20 Aug 2018, 00:19
y = kx + 3
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
17=2K+3 K=14/2=7
y=7*4+3=31



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Re: In the equation above, k is a constant. If y = 17 when x = 2
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20 Aug 2018, 06:06
Bunuel wrote: y = kx + 3
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34 (B) 31 (C) 14 (D) 11 (E) 7 \(y = kx + 3\) Substitute \(y = 17\) & \(x = 2\) in the above equation Or, \(17 = k*2 + 3\) Or, \(2k = 14\) Or, \(k = 7\) Quote: what is the value of y when x = 4 ? Substitute x = 4 in the equation \(y = kx + 3\) Or, \(y = 7*4 + 3\) So, \(y = 31\), Answer must be (B)
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Re: In the equation above, k is a constant. If y = 17 when x = 2
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20 Aug 2018, 08:03
\(y=kx+3\) \(17=2k+3\) \(k=7\) now \(y=4*7+3\) \(y=31\)
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