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# In the figure above, ABCD is a square, and P and Q are the centers of

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In the figure above, ABCD is a square, and P and Q are the centers of  [#permalink]

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07 Oct 2016, 01:37
00:00

Difficulty:

55% (hard)

Question Stats:

64% (01:42) correct 36% (01:45) wrong based on 154 sessions

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In the figure above, ABCD is a square, and P and Q are the centers of identical semicircles BF and AE, respectively. If DE=EA=AF=FB=1, then what is the perimeter of the shaded region?

A. 4+π/2
B. 6
C. 8
D. 6+π
E. 6+2π

Attachment:

T6357.png [ 5.24 KiB | Viewed 1928 times ]

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In the figure above, ABCD is a square, and P and Q are the centers of  [#permalink]

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07 Oct 2016, 04:14
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1
Given data
DE=EA=AF=FB=1

Radius of the semicircles are 1/2.
Circumference of the semicircle = pi * radius = pi/2
Also side of the square is 2(DE+EA).

Perimeter = 2+2+1(DE)+1(AF)+$$\frac{\pi}{2}$$(perimeter of semi-circle1)+$$\frac{\pi}{2}$$(perimeter of semi-circle2) = $$6 + \pi$$

Therefore, perimeter of the shaded region is $$6 + \pi$$ (Option D)
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Re: In the figure above, ABCD is a square, and P and Q are the centers of  [#permalink]

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17 Feb 2018, 10:51
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Re: In the figure above, ABCD is a square, and P and Q are the centers of  [#permalink]

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23 Oct 2018, 15:22
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Top Contributor
Bunuel wrote:

In the figure above, ABCD is a square, and P and Q are the centers of identical semicircles BF and AE, respectively. If DE=EA=AF=FB=1, then what is the perimeter of the shaded region?

A. 4+π/2
B. 6
C. 8
D. 6+π
E. 6+2π

Attachment:
T6357.png

We can see that each side of the square has length 2

At this point, we can see that the perimeter consists of some STRAIGHT parts and some CURVED parts

Since the curved parts are SEMICIRCLES, we can use the circumference formula, which says: circumference = (diameter)(π)
Since a semiCIRCLE is half of a circle, we can say: perimeter of a SEMIcircle = (1/2)(diameter)(π)

Since each semicircle has diameter 1, the perimeter of 1 semicircle = (1/2)(1)(π) = π/2

So, the perimeter of the given figure = 2 + 2 + 1 + 1 + π/2 + π/2
= 6 + π

Cheers,
Brent
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Re: In the figure above, ABCD is a square, and P and Q are the centers of   [#permalink] 23 Oct 2018, 15:22
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