Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: In the figures above, if the area of the triangle on the right is twic [#permalink]

Show Tags

15 Mar 2010, 09:29

With the property ratio of area in similar triangle = (ratio of any similar side)^2 so s/S = sqrt(1/2) => S = s*sqrt(2) hence C is the answer
_________________

Re: In the figures above, if the area of the triangle on the right is twic [#permalink]

Show Tags

21 Mar 2010, 12:10

mustdoit wrote:

nickk wrote:

seems easy enough....

for similar triangles (all angles the same) the following holds:

(area A)/(area b) = ( x/y )^2 (where x and y are corresponding lengths)

in this case, let A be the area of the smaller triangle. We have:

2A/A = (S/s)^2 => S/s = 2^0.5 S = s*2^0.5

Where does this property comes from??

This is the similar trianlges property. Any two triangles are similar if they have same corresponding angles or if the ratio of their corresponding sides are same. In case two triangles are similar, ratio of their areas = (ratio of side)^2
_________________

I eliminated A and B for this because I knew that S had to be greater than s, but I did not know how to find the exact answer. I also eliminated 2s because that excludes the height when calculating area, but again I could not figure out how to get the exact answer. Any help please?? Thanks!!! The file is attached.

Re: In the figures above, if the area of the triangle on the right is twic [#permalink]

Show Tags

05 May 2016, 07:06

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

There’s something in Pacific North West that you cannot find anywhere else. The atmosphere and scenic nature are next to none, with mountains on one side and ocean on...

Joe Navarro is an ex FBI agent who was a founding member of the FBI’s Behavioural Analysis Program. He was a body language expert who he used his ability to successfully...