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Math Revolution GMAT Instructor V
Joined: 16 Aug 2015
Posts: 8001
GMAT 1: 760 Q51 V42 GPA: 3.82
In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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Difficulty:   65% (hard)

Question Stats: 50% (01:49) correct 50% (02:23) wrong based on 111 sessions

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In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0). If these 4 points makes a rectangle, what is the probability that x+y<4?
A. 1/2
B. 1/3
C. 1/4
D. 1/5
E. 2/5

*Answer will be posted in 2 days.

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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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Solved using the areas of the triangle rectangle.
Math Revolution GMAT Instructor V
Joined: 16 Aug 2015
Posts: 8001
GMAT 1: 760 Q51 V42 GPA: 3.82
Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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As you can see from the diagram below, the correct answer is 1/3. Hence, B is our answer choice.
Attachments 1.png [ 10.85 KiB | Viewed 2063 times ]

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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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MathRevolution wrote:
As you can see from the diagram below, the correct answer is 1/3. Hence, B is our answer choice.

Can you please share the complete solution, but in the question it is mentioned as x+y < 4.
Retired Moderator G
Joined: 26 Nov 2012
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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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Senthil1981 wrote:

Solved using the areas of the triangle rectangle.

Please share us the method that you used to solve this question, please share us in detail.
Senior Manager  Joined: 02 Mar 2012
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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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msk0657 wrote:
Senthil1981 wrote:

Solved using the areas of the triangle rectangle.

Please share us the method that you used to solve this question, please share us in detail.

as shown in above figure the line x+y<4 shows a triangle.
the area of triangle =1/2*4*4=8

are od rectangle given =4*6=24

probability any point lies x+y<4 in rectangle given is =8/24=1/3
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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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MathRevolution wrote:
As you can see from the diagram below, the correct answer is 1/3. Hence, B is our answer choice.

Can you please explain why do we take (0,4) and (4,0) to form a triangle and not (0,3) and (3,0) ?
We want x+y to be <4.
At the point (0,4) , x=0 and y=4 , hence x+y are not <4.
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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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1
This question isn't very clear in what it is asking. I thought it wanted the probability of selecting an x+y < 4 value from the endpoints given. It's just too ambiguous
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In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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Bunuel karishma Could you please explain why do we take (0,4) and (4,0) to form a triangle and not (0,3) and (3,0) ?
We want x+y to be <4.
At the point (0,4) , x=0 and y=4 , hence x+y are not <4. What am I missing here?
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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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MathRevolution wrote:
As you can see from the diagram below, the correct answer is 1/3. Hence, B is our answer choice.

How is X+Y<4?
If you have posted a question can you also provide a proper solution? Not everyone is brilliant in maths
Intern  Joined: 15 Oct 2017
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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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I am too, having a problem comprehending this question.
If x+y < 4, why the area included (4, 0) & (0, 4) ?
I'm quite sure you meant x+y <= 4, otherwise, we cannot calculate this using areas.
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Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).  [#permalink]

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_________________ Re: In the x- y plane, there are 4 points (0,0), (0,4), (6,4), and (6,0).   [#permalink] 28 Feb 2019, 10:25
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