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16 Oct 2025, 00:20
Kudos
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C
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Difficulty:
25%
(medium)
Question Stats:
82% (01:38) correct
18%
(01:30)
wrong
based on 71
sessions
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Initially, how many black chips are in a box containing only red chips and black chips, all identical except for color?
(1) Initially, the ratio of red chips to black chips in the box is 3/25.
(2) If 12 red chips and 80 black chips are removed from the box, the probability of randomly drawing a red chip from the box is 1/11.
(1) Initially, the ratio of red chips to black chips in the box is 3/25.
(2) If 12 red chips and 80 black chips are removed from the box, the probability of randomly drawing a red chip from the box is 1/11.
16 Oct 2025, 07:22
Kudos
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Bunuel
The chips are of two colours , red R and black B only.
We need to find the number of Black chips .
Statement 1:
(1) Initially, the ratio of red chips to black chips in the box is 3/25.
R / B = 3 / 25
Hence, insufficient
Statement 2:
(2) If 12 red chips and 80 black chips are removed from the box, the probability of randomly drawing a red chip from the box is 1/11.
(R-12) / (R-12+B-80) = (1/11)
11R - 132 = R+ B - 92
10R = B + 40
Hence, Insufficient
Combining both Statements 1 and 2, we get
B = (25/3)*R
(25/3)*R = 10R - 40
25R = 30R - 120
5R = 120, then R = 24
Then, B = 10*24 - 40
B = 200
Hence, Sufficient
Option C
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