sometime plugging in is easy way to solve these kind of problems.

the question says x is an

integer. this statement gives half solution.

1: since x is an integer, x cannot be +ve. so it must be -ve. so A is suff.

2: since x is an integer, x can be either -ve or +ve. so not suff.

jallenmorris wrote:

A

1) Sufficient. This has to be an integer (fractions would really change up the answer to this one). So with a negative number, when you cube it, you come up with a smaller (to the left on the number line) negative number. x = -2. x^3 = -8. -2 > -8. What if x is positive? x = 2, x^3 = 8. 2 !> 8 ( ! = not in programming). Since we are to take the statements as true, a value that does not conform to the statement is not possible. The only values that are possible to make #1 true are negative numbers. So the answer to the question posed is "No, x is not positive." and the data presented is sufficient.

2) Insufficient. we have x < x^2. x = -2...so x^2 = 4. -2 < 4 => TRUE. x = 2, x = 4 2 < 4 =>TRUE. We have one negative number that works for statement 2 and one positive number for statement 2. This is not enough to give a difinitive answer as to whether x is positive.

aaron22197 wrote:

Is integer x positive?

1. \(x \gt x^3\)

2. \(x \lt x^2\)

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