Is x > 4?

Is x>4?

(1) (x+1)^2>4

Approach #1: \((x+1)^2>4\) --> \(x+1<-2\) or \(x+1>2\) --> \(x<-3\) or \(x>1\). Not sufficient.
Approach #2: \((x+1)^2>4\) --> \(x^2+2x-3>0\) --> \((x+3)(x-1)>0\) --> \(x<-3\) or \(x>1\). Not sufficient.
Graphic representation:
True range of x:

(2) (x-1)^2>4

Approach #1: \((x-1)^2>4\) --> \(x-1<-2\) or \(x-1>2\) --> \(x<-1\) or \(x>3\). Not sufficient.
Approach #2: \((x-1)^2>4\) --> \(x^2-2x-3>0\) --> \((x+1)(x-3)>0\) --> \(x<-1\) or \(x>3\). Not sufficient.
Graphic representation:
True range of x:


(1)+(2) Intersection of the ranges from (1) and (2) is \(x<-3\) or \(x>3\): Not sufficient.

Answer: E.

P.S. Of course if you notice that some big enough positive number, for example \(y=10>4\), satisfies both statements and gives an answer YES and some small enough negative number, for example \(y=-10<4\), also satisfies both statements and gives an answer NO you'll get the answer E right away.