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Kevin, Leo, and Max each received a monetary award for their work on project X. If the total of the 3 awards was $705, was the average (arithmetic mean) of the 3 awards equal to the median of the 3 awards?

(1) Kevin's award was $235.

(2) Leo's award was $70 greater than Max's award.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.
­
Total of the 3 = 705
Average of the 3 = 705/3 = 235

Now think, in a list of 3 numbers, if one is at the average, what are the possibilities for the other two? There are two possibilities:
- Either the other two are also at the average. All 3 numbers are same here and all are at the median. 
- Or one is less than the average and then the other must be greater. (deficit = excess). The average lies at the middle and is the median.

Hence, in either case, median will be the average only. 

(1) Kevin's award was $235.
Since average is 235 and Kevin is at the average, median must be 235 too. 
Sufficient.

(2) Leo's award was $70 greater than Max's award.
Median could take many different values: 1, 71, 633  (Median = 71)
or 200, 235, 270 (Median = 235)
Not sufficient. 

Answer (A)

Check out another interesting question on Mean and Median here:
https://anaprep.com/sets-statistics-mea ... -question/
 ­
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I found A not to be true - since nothing says all 2 awards cannot be same. So by that logic A is not sufficient.
Bunuel
Kevin, Leo, and Max each received a monetary award for their work on project X. If the total of the 3 awards was $705, was the average (arithmetic mean) of the 3 awards equal to the median of the 3 awards?

Since the total of the 3 awards was $705, the average was 705/3 = $235.

(1) Kevin's award was $235.

Since Kevin's award of $235 matches the average, then one of the remaining two awards must have been less than or equal to that amount, and the other must have been more than or equal to that amount. Consequently, the awards were {≤235, 235, ≥235}. Therefore, the median, which is the middle value, would also be equal to 235, and hence, to the average. Sufficient.

(2) Leo's award was $70 greater than Max's award.

The above is clearly insufficient. For instance consider: {0, 70, 635} and {200, 235, 270}.

Answer: A.
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I found A not to be true - since nothing says all 2 awards cannot be same. So by that logic A is not sufficient.
Bunuel
Kevin, Leo, and Max each received a monetary award for their work on project X. If the total of the 3 awards was $705, was the average (arithmetic mean) of the 3 awards equal to the median of the 3 awards?

Since the total of the 3 awards was $705, the average was 705/3 = $235.

(1) Kevin's award was $235.

Since Kevin's award of $235 matches the average, then one of the remaining two awards must have been less than or equal to that amount, and the other must have been more than or equal to that amount. Consequently, the awards were {≤235, 235, ≥235}. Therefore, the median, which is the middle value, would also be equal to 235, and hence, to the average. Sufficient.

(2) Leo's award was $70 greater than Max's award.

The above is clearly insufficient. For instance consider: {0, 70, 635} and {200, 235, 270}.

Answer: A.

Yes, the awards do not have to be different. The solution does not assume that. Notice the use of ≤ and ≥ in the explanation? Even if the awards are equal, 235, 235, 235, the median, which is the middle value, would still be 235. So statement (1) is sufficient.
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