GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Jan 2019, 11:59

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
• ### FREE Quant Workshop by e-GMAT!

January 20, 2019

January 20, 2019

07:00 AM PST

07:00 AM PST

Get personalized insights on how to achieve your Target Quant Score.
• ### GMAT Club Tests are Free & Open for Martin Luther King Jr.'s Birthday!

January 21, 2019

January 21, 2019

10:00 PM PST

11:00 PM PST

Mark your calendars - All GMAT Club Tests are free and open January 21st for celebrate Martin Luther King Jr.'s Birthday.

# Let P stand for the product of the first 5 positive integers. What is

Author Message
TAGS:

### Hide Tags

General GMAT Forum Moderator
Joined: 29 Jan 2015
Posts: 1095
Location: India
WE: General Management (Non-Profit and Government)
Let P stand for the product of the first 5 positive integers. What is  [#permalink]

### Show Tags

Updated on: 17 May 2017, 07:15
00:00

Difficulty:

15% (low)

Question Stats:

87% (01:07) correct 13% (01:18) wrong based on 23 sessions

### HideShow timer Statistics

Let P stand for the product of the first 5 positive integers. What is the greatest possible value of m if P/10^m is an integer?

(A) 1
(B) 2
(C) 3
(D) 5
(E) 10

_________________

If you liked my post, kindly give me a Kudos. Thanks.

Originally posted by rohan2345 on 17 May 2017, 05:49.
Last edited by Bunuel on 17 May 2017, 07:15, edited 1 time in total.
Renamed the topic.
Manager
Joined: 27 Mar 2016
Posts: 51
Re: Let P stand for the product of the first 5 positive integers. What is  [#permalink]

### Show Tags

17 May 2017, 06:28
Product of first 5 integers = 120
So m should be 1

Sent from my ONEPLUS A3003 using GMAT Club Forum mobile app
Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4342
Location: India
GPA: 3.5
Re: Let P stand for the product of the first 5 positive integers. What is  [#permalink]

### Show Tags

17 May 2017, 07:58
rohan2345 wrote:
Let P stand for the product of the first 5 positive integers. What is the greatest possible value of m if P/10^m is an integer?

(A) 1
(B) 2
(C) 3
(D) 5
(E) 10

Product of the first 5 positive integers = P = 5! = 120

Given, $$\frac{P}{10^m}$$ must be an integer so -

$$\frac{120}{10^m}$$ must be an integer

Since p has only 1 trailing zero the value of m can not exceed 1

Thus, answer must be (A) 1
_________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )

Re: Let P stand for the product of the first 5 positive integers. What is &nbs [#permalink] 17 May 2017, 07:58
Display posts from previous: Sort by