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M0-1 Q 26

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Manager
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M0-1 Q 26 [#permalink]

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New post 21 Mar 2009, 04:26
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can someone confirm that a +ve can be conisdered a multiple of itself?

I could not anwer this question properly, as I did not consider this case.
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Re: M0-1 Q 26 [#permalink]

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New post 21 Mar 2009, 12:07
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Well to answer this quesiton : is x prime

x can be prime only if it is two divisors 1 and itself.

Option 1 says x is a multiple of a prime number - This statement introduces the ambiguity. The integer x has a multiple. The multiple could be itself or another prime number.

Eg : x = 2*3 = 6 ; x=2*1 = 2. So not sufficient;

Option 2 says x is a product of two integers - which is essentially the same as option 1. So insufficient.

Taking them together doesn't add much value since option 2 is just restating option 1.

Hence the answer is E.

To answer your question - any integer can be considered a multiple of itself. 2 is a multiple of itself : 2*1 = 2. -2 is also a multiple of itself : -2*1=-2.
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Re: M0-1 Q 26 [#permalink]

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New post 22 Mar 2009, 05:11
Well said. It took a while but I realized 1 was insufficient and so was 2 since 2 was similar to 1. So answer was E.

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Re: M0-1 Q 26   [#permalink] 22 Mar 2009, 05:11
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