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At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If there are two-thirds more males than females, what fraction of the students speak a foreign language?

Explanation of this question translates number of male=2/3f (f being the number of females)

I think we cannot translate 2/3 more males than females to 2/3f

I'm not positive but to me, it sounds like this: two-thirds more males than females -> e.g. assume there are 90 students... if there are 2/3 more males than females, then there are 60 more males than females, so 90 = #females + 60 + #females 30 = 2* # females

females = 15 males = 75

So the # of females would actually be 1/5 the number of males.

I believe OP is correct. There seems to be an issue with the problem.

2/3 more males than females should translate to m = (5/3)f. Indeed, based on just the wording, we should expect to have a greater number of males than females.

Looking at the OA, the table shows fewer males than females, and based on the above that is incorrect.

At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If the number of males is two-thirds the number of females, what fraction of the students speak a foreign language?

I think ans is OB = 3/5 we know ... Foreign speaking male (3/4M) and female (1/2F) the number of males is two-thirds the number of females = M=2/3 F or F = 3/2 M