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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
Machine M processes a certain chemical product at a constant rate. Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
(2) Machine M processes the product at a rate that is less than 95 kilograms per hour

\(M_R > 25 gm/s\)

statement 1:
\(M_R > \frac{92 *1000}{60*60}\)
\(M_R > 25.x\)
sufficient

statement 2:
\(M_R < \frac{95 *1000}{60*60}\)
\(M_R < 26.x\)
not sufficient

Ans: A
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
1
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Machine M processes a certain chemical product at a constant rate. Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
(2) Machine M processes the product at a rate that is less than 95 kilograms per hour

Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?
As we can see that answer choices are in kilograms per hour. BUT the question is in grams per second.
So , 25 *(grams/second)= 25 *(3600/1000) kilograms per hour 1 gm=(1/1000) kilograms ; 1 sec=(1/3600) hour
25 *(grams/second)=90 kilograms per hour

1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
Always True, M process the product at a rate that is greater than 90 kilograms per hour
Sufficient.

2) Machine M processes the product at a rate that is less than 95 kilograms per hour
what if , M processes 92 kg. True
what if , M processes 80 kg. False
Insufficient

A is our Answer.
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
#1
Machine M processes the product at a rate that is greater than 92 kilograms per hour
let total be 93 ; or say 93000 gms
net rate = 93000/3600 ; 25.8 i.e >25
also net rate at 92.1*1000/3600 is 25.5
sufficient
#2
Machine M processes the product at a rate that is less than 95 kilograms per hour
clearly insufficient
as we get yes and no
OPTION A is correct


Machine M processes a certain chemical product at a constant rate. Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
(2) Machine M processes the product at a rate that is less than 95 kilograms per hour
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
1
Kudos
Quote:
Machine M processes a certain chemical product at a constant rate. Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
(2) Machine M processes the product at a rate that is less than 95 kilograms per hour


25g/s=(25/1000)kg/s
(25*3600/1000)kg/hr=90

(1) sufic
rate: 92>90

(2) insufic
0<rate<95

ans (A)
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
1
Kudos
Machine M processes a certain chemical product at a constant rate. Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
(2) Machine M processes the product at a rate that is less than 95 kilograms per hour
1)92000/3600 = 26.xx, so greater than 25 g/sec
sufficient
2)>95000/3600 = [<27.xxx] may or may not be greater.
insufficient
Ans A
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
2
Kudos
25grams per second
25*60= 1500 grams per minute
1500*60 = 90000 grams per hour = 90 kgs per hour
---> Rate > 90 kgs per hour ???

(Statement1): Rate > 92 kgs per hour
Clearly Sufficient

(Statement2): Rate < 95 kgs per hour

Rate could be < 90 kgs per hour (NO)
Or
90 kgs per hour < Rate < 95 kgs per hour (YES)
Insufficient

Answer (A).
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
Answer A but lord what a mind twist :o
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
1
Kudos
Machine M processes a certain chemical product at a constant rate. Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
(2) Machine M processes the product at a rate that is less than 95 kilograms per hour

1) 92 kg per hour = 92,000/ 60*60 = 920/36 >> greater than 25 .SUFFICIENT
2) Clearly not sufficient.
A is the answer.
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Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
4
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Originally i approached this Q as converting the given info from each statement to g/hour to match the stimulus given then comparing. However since we only have 2 mins per question, we want to use the fastest & most efficient way. Imo is to convert the given information aka 25g/hour to 90kg/hour, then compare to each statement. The reason for this is because you only have to convert once since both statements give the information in kg/hour.

Question asks, is rate > 90kg/hour

1) We can see this is sufficient since 92kg/hour is > 90kg/hour
2) We can see this is not sufficient since less than 95kg/hour could be 94,93,92,91 etc... but also less than 90kg/hour like 89,88. Any number less than 90 essentially.

Therefore A = Answer
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
Asked: Machine M processes a certain chemical product at a constant rate. Does machine M process the product at a rate that is greater than 25 grams per second= (1 kilogram = 1000 grams)?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour
Machine M processes the product at a rate that is greater than 92 kilograms per hour = 92*100/60*60 = 25.5 grams/seconds > 25 grams/second
SUFFICIENT

(2) Machine M processes the product at a rate that is less than 95 kilograms per hour
NOT SUFFICIENT

IMO A
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
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So, I see that (1) is sufficient alone and (2) is not sufficient alone. But, if you take 1 and 2 together, 2 becomes sufficient because it produces a range that narrows the field so that you know it's sufficient.
So if 1 can stand alone, but 2 depends on 1 to be useful, is the answer always still A? I had answered this as C.
Thanks!
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
jbanan wrote:
So, I see that (1) is sufficient alone and (2) is not sufficient alone. But, if you take 1 and 2 together, 2 becomes sufficient because it produces a range that narrows the field so that you know it's sufficient.
So if 1 can stand alone, but 2 depends on 1 to be useful, is the answer always still A? I had answered this as C.
Thanks!


Answer is A. Any value in statement 1 satisfies the question of a value of greater than 90 kilograms. We don't need statement 2 to further narrow the values.
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
To convert grams per second to kilograms per hour, multiply by 18/5.

25 * (18/5) = 90 kilograms. The question is: Does machine M process the product at a rate that is greater than 90 kilograms per per hour?

(1) Machine M processes the product at a rate that is greater than 92 kilograms per hour

92 > 90. Sufficient.

(2) Machine M processes the product at a rate that is less than 95 kilograms per hour

Could be greater or less than 90. Insufficient.

Answer is A.
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
Would someone be able to give me tips for how to convert quickly with large numbers that are not evenly divisible? In particular, how to divide by 3600 quickly? St1 - 92000/3600 is cumbersome and really borderline 25 grams so it's not easy to round up to 4k or the like.
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
I also am not the quickest doing division etc. of those large numbers. I think the easiest is to convert the stem into the format of the answer choices straight away, and then the problem is very quickly solved if you just see 25g/s --> 90kg/hr.

That trick helps me anway.

CEdward wrote:
Would someone be able to give me tips for how to convert quickly with large numbers that are not evenly divisible? In particular, how to divide by 3600 quickly? St1 - 92000/3600 is cumbersome and really borderline 25 grams so it's not easy to round up to 4k or the like.
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
These questions are a time suck if you convert at the statement level, however luckily the units between the two statements always match.

So front load the conversion by quickly glancing at the statements to see in what units the rates are presented. Then convert the main rate to match those units and voila :)
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Re: Machine M processes a certain chemical product at a constant rate. Doe [#permalink]
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