NEW HERE? LEARN MORE
closeclose
Last visit was: 24 Apr 2024, 11:04 It is currently 24 Apr 2024, 11:04
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

Mr. Kramer, the losing candidate in a two-candidate

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
Curly05
Eternal Intern
Joined: 07 Jun 2003
Posts: 297
Own Kudos [?]: 1480 [113]
Given Kudos: 0
Location: Lone Star State
Send PM
Mr. Kramer, the losing candidate in a two-candidate [#permalink] New post   Updated on: 25 Apr 2014, 01:44
3
Kudos
110
Bookmarks
00:00
A
B
C
D
E

Difficulty:

55% (hard)

Question Stats:

67% (02:22) correct 33% (02:50) wrong based on 1654 sessions
Hide Show timer Statistics
Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

A. 10%
B. 12%
C. 15%
D. 17%
E. 20%
ShowHide Answer
Official Answer
D

Originally posted by Curly05 on 21 Jul 2003, 16:35.
Last edited by Bunuel on 25 Apr 2014, 01:44, edited 1 time in total.
Added the OA.
Most Helpful Reply
User avatar
srijay007
Senior Manager
Senior Manager
Joined: 05 May 2004
Posts: 339
Own Kudos [?]: 209 [60]
Given Kudos: 0
Location: San Jose, CA
Send PM
Re: PS percentage problem [#permalink] New post   11 Jul 2004, 20:40
38
Kudos
22
Bookmarks
1 min
Assume there are 100 votes
Kramer has 40 and the winner has 60
Kramer needs atleast 50 which means atleast 10 out of 60 which is 16.67%
Hence I'll go with D
User avatar
AkamaiBrah
GMAT Instructor
Joined: 07 Jul 2003
Posts: 392
Own Kudos [?]: 468 [16]
Given Kudos: 0
Location: New York NY 10024
Concentration: Finance
Schools:Haas, MFE; Anderson, MBA; USC, MSEE
Send PM
Re: PS: What's a Quick Way to Get This? [#permalink] New post   21 Jul 2003, 18:16
12
Kudos
4
Bookmarks
Curly05 wrote:
14. Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all the votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?


Divide the vote into 10 parts. He got 4 parts, he needs 5 parts. So he need 1 part out of the remaining 6 parts or .166666666...% -- plus one vote.
General Discussion
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64897 [2]
Given Kudos: 426
Location: Pune, India
Send PM
Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink] New post   28 Feb 2022, 22:33
1
Kudos
1
Bookmarks
Expert Reply
Curly05 wrote:
Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

A. 10%
B. 12%
C. 15%
D. 17%
E. 20%


Let me point out here that a 6 digit number as insane as this, is a giveaway that it doesn't need to be used. Among the larger numbers, it's a good idea to be familiar with the exponents of primes such as 1024, 729, 4096, 3125 etc and of course our special number 1001. But a number as huge and as random as 942,568 is too tedious.
User avatar
S
thisisit25
Manager
Manager
Joined: 11 Apr 2021
Posts: 70
Own Kudos [?]: 64 [2]
Given Kudos: 464
Send PM
Reviews Badge
Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink] New post   06 Jan 2023, 09:21
2
Kudos
Curly05 wrote:
Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

A. 10%
B. 12%
C. 15%
D. 17%
E. 20%


Let total votes won by Kramer be --> z (given = 942,568)
Let all votes cast be --> t

Given: z = 0.4t
Find: What % of remaining votes are needed to make Kramer's total go up from 40% to 50%?

Let votes required by k% of remaining.
Remaining = t - 0.4t = 0.6t
We also know that Kramer only needs 10% of the total more (already had 40% of total)
So,
0.6t * k/100 = 0.1t
t gets cancelled -->
k = 0.1 * 100 / 0.6 = 16.6667
User avatar
bumpbot
Non-Human User
Joined: 09 Sep 2013
Posts: 32650
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink] New post   09 Jan 2024, 12:08
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
gmatclubot
Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]
09 Jan 2024, 12:08
Moderators:
Bunuel
Math Expert
92902 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions