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One pump drains one-half of a pond in 3 hours, and then a second pump [#permalink]

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16 Oct 2011, 09:55

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One pump drains one-half of a pond in 3 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone?

A. 1 hour B. 1.2 hour C. 3 hours D. 5 hours E. 6 hours

Re: One pump drains one-half of a pond in 3 hours, and then a second pump [#permalink]

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16 Oct 2011, 10:56

saumzi wrote:

i know its terribly easy but still i m stuck somewhere...

One pump drains one-half of a pond in 3 hours, and then a second pump starts draining the pond.The two pumps working together finish emptying the pond in one-half hour.How long would it take the second pump to drain the pond if it had to do the job alone???

A.1 hour B.1.2 hour C.3 hours D.5 hours E.6 hours

Can you please check the question? I am getting the answer which is not in option.

Pump 1 drains half of the pond in 3 hrs ==>it will take 6hrs for Pump 1 to drain the entire pond. Number of hrs taken by pump 2 = Y If both pumps working together will empty the pond in 1.5hrs==>3/2 ==>1/6 + 1/Y = 2/3 ==>1/Y = 2/3-1/6 ==>(4-1)/6 =1/2 Y =2 Number of hrs taken by Pump 2 to drain the entire pond = 2hrs
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Re: One pump drains one-half of a pond in 3 hours, and then a second pump [#permalink]

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27 Jan 2016, 10:17

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This post received KUDOS

saumzi wrote:

i know its terribly easy but still i m stuck somewhere...

One pump drains one-half of a pond in 3 hours, and then a second pump starts draining the pond.The two pumps working together finish emptying the pond in one-half hour.How long would it take the second pump to drain the pond if it had to do the job alone???

A.1 hour B.1.2 hour C.3 hours D.5 hours E.6 hours

The tricky part here, I believed is one half hour = 1/2. Then everything would be easy.

We have the 1st pump working rate/hour = 1/2 : 3 = 1/6 Working rate of 2 pumps: 1/2 : 1/2 = 1. Working rate of 2nd pump: 1 -1/6 = 5/6 --> Time taken for the 2nd pump to finish: 1 : 5/6 = 6/5 = 1.2 hours. Hope it help
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Re: One pump drains one-half of a pond in 3 hours, and then a second pump [#permalink]

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27 Jan 2016, 20:04

First pump drains 1/2 of the tank in 3 hours so 6 hours it will take to drain the full tank. Let, 2nd pump drains the full tank in a hours so both together can drain (1/6+1/a) part in 1 hour son in 1/2 hour they drain 1/2*(1/6+1/a) part of the tank given that in 1/2 hour they drain 1/2 of the tank hence we can say 1/2*(1/6+1/a) = 1/2 solving u get a = 6/5=1.2 Hence answer is B
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One pump drains one-half of a pond in 3 hours, and then a second pump [#permalink]

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17 Feb 2016, 15:48

if pump 1 drains 1/12 of pond in 1/2 hour, then pump 2 must drain 1/2-1/12=5/12 of pond in 1/2 hour let t=pump 2's time to drain entire pond alone (5/12)/(1/2))=1/t t=1.2 hours

Re: One pump drains one-half of a pond in 3 hours, and then a second pump [#permalink]

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13 Aug 2017, 18:57

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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: One pump drains one-half of a pond in 3 hours, and then a second pump [#permalink]

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13 Aug 2017, 19:48

Let the total capacity of pond be 6. Pump 1 drains 3 in 3 hrs, i.e. 1 per hour both pumps finishes draining remaining 3 in 0.5 hour, i.e 6 per hour Thus rate of pump 2 has to be (total rate - rate of pump 1) = (6-1) = 5 per hour Pump 2 needs to drain complete 6 @ 5 per hour so time taken is \(\frac{6}{5}\) = 1.2 hrs
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