Given:
Total = 80
CC = 40% × 80 = 32
S = 50% × 80 = 40
D = 30% × 80 = 24
S ∩ D only (not CC) = 5
Maximize CC ∩ D (not S) ->we want max
To maximize CC ∩ D only, minimize all other groups within Design.
Set "All three depts" = 0 & Set "Design only" = 0
24 (total in D) = 5 (S ∩ D only) + CC ∩ D only
→ CC ∩ D only = 19
Feasibility check: (CC ∩ D only = 19, All three depts = 0)- D only = 24 − (5+19+0) = 0 Must be ≥ 0.
- CC remaining = 32 − 19 − 0 = 13 Must be ≥ 0.
- S remaining = 40 − 5 − 0 = 35 Must be ≥ 0.
Total = 13 + 35 + 0 + 0 + 19 + 5 + 0 = 72 ≤ 80 (8 employees in none of these departments)
Answer: 19
Maxsmdt041197
Question was:
In a company of 80 employees, 40% of the employees are in customer care, 50% are in sales, and 30% are in design. If 5 employees are a part of both the sales and design departments, but not in customer care, what is the maximum number of employees who are in both customer care and design, but not sales?A) 19 - right solutionB) 28C) 32D) 36E) 40So what did I do:CC: 80*0,4 = 32S: 80*0,5 = 40D: 80*0,3 = 24 If there are 5 in both S and D but not CC: CC only stays 32S only: 40-5 = 35 D only: 24-5 = 19S and D: = 5Total still over 80: 32+25+19+5= 91x represents CC and D (employees in both): 35+5+19-x+32-x+x = 80Because employees in both are added and subtracted in the "only categories"x = 11New distribution:S = 35S/D = 5D = 19-11= 8CC = 32-11 = 21D/CC = 11Lets check: 35+5+8+21+11 = 80 but 11 is not a possible answer, at is point I am stuckThanks so much for your help!