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rajatchopra1994
A can do a piece of work in 12 days. B can do this work in 16 days. A started the work alone. After how many days should B join him, so that the work is finished in 9 days?

A. 2 days
B. 3 days
C. 4 days
D. 5 days
E. 1 day

Another way:

Let A work for \(n\) days , so work done \(= \frac{n}{12\)

Remaining work = \(1- \frac{n}{12} = \frac{12 -n }{12}\)

A + B can do the whole work in \(\frac{1}{12} + \frac{1}{16} = \frac{1}{t},\hspace{2mm} t= \frac{48}{7} \)

If together whole work can be done in \( \frac{48}{7} \) days

Then remaining work : \(\frac{12 -n }{12}\) can be done together in \(\frac{48}{7} *\frac{12 -n }{12}\) days

We know it took total of \(9 \) days , hence:

A alone + ( A+B together ) = \(9\)

\(n + \frac{48}{7} *\frac{12 -n }{12} = 9 \)

\(36n =180\)

\(n= 5\)

Ans- D

Hope it's clear.
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