For a bake sale, Simon baked 2n more pies than Theresa. Theresa baked

Question

For a bake sale, Simon baked 2n more pies than Theresa. Theresa baked half as many pies as Roger, who baked  \frac{1}{3}n  pies. No other pies were baked for the sale. What fraction of the total pies for sale did Roger bake?

A.  \frac{1}{16}

B.  \frac{1}{8}

C.  \frac{3}{16}

D.  \frac{3}{8}

E.  \frac{13}{16}

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Purnank · Answer

Given - For a bake sale, Simon baked 2n more pies than Theresa. Theresa baked half as many pies as Roger, who baked n/3 pies. No other pies were baked for the sale.

From this lets form table

Roger         Theresa           Simon           Total
 n/3               n/6            n/6 + 2n          8n/3

So, fraction of the total pies for sale did Roger bake = (n/3) / (8n/3)  = 1/8.
Hence B.

Shwarma · Answer

Option B 
R= 1/3 n
T= 1/6 n
S= 2n+(1/6)n

Total =2n+(2/3)n

Roger fraction = (1/3)n/(2n+(2/3)n) = 1/8n

mansi_gupta · Answer

Hi, I have just started my GMAT prep. 
I was solving this problem by assumption, theresa baked let's say 10 pies, so the total no of pies will be n= 60. How can i find the real fraction of pies baked by Roger ??

I need help with getting to the solution with this method, but do let me know if this approach is incorrect.

Purnank · Answer

Yes we can solve this by assumption as well,
If theresa baked  10  pies (Theresa baked half as many pies as Roger) means Roger count is  20 . which is n/3 right? 
Therefore  n = 60 .
Now lets check for simon (Simon baked 2n more pies than Theresa), Simon count =  2*60 + Theresa count.  =  130
Therefore total pies = 10+20+130 = 160
So, Rogers fraction is = 20 / 160 = 1/8.

btsaami · Answer

I think for using fraction directly is easy. But an alternative way can also be used.
We see that n is a multiple of multiple of 6 and as i can see that the option has either 8 or 16, so i started safe by plugging the value of n by taking LCM of 6 and 16= 48. i.e. n=48

From the question, we have
R=n/3= 48/3=16
T= R/2 = 16/2 =8
S= T+2*n= 8+2*48 =8+96= 104
Total= 104+16+8= 128

R/Total= 16/128= 1/8.

I just took this case for a safer side. we can take other multiples of 6 as well.

For a bake sale, Simon baked 2n more pies than Theresa. Theresa baked

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GMAT Problem Solving (PS) Questions

For a bake sale, Simon baked 2n more pies than Theresa. Theresa baked

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