GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Jul 2018, 13:31

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Please Crack the Math (PS) Question! Anyone! Thanks ;)

Author Message
Intern
Joined: 23 Jun 2009
Posts: 47

### Show Tags

21 Jul 2009, 22:07
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

A certain city with a population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum population that the least populated district could have?
A) 10,700
B) 10,800
C) 10,900
D) 11,000
E) 11,100

It was from the GMAT Prep. Thanks!

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Manager
Joined: 10 Jul 2009
Posts: 149

### Show Tags

21 Jul 2009, 22:20
2
Out of 11 districts, one district can have least population when the remaining 10 have the maximum possible population.
Let x be the average population of the 11 districts. Since a maximum deviation of 10% is allowed, the population for the 10 districts is (110/100)*10*x = 11x

Population of the least populated district = x
Total population = 11x + x = 132000
12x = 132000
x = 11000

So least populated district can have min population of 11000
Intern
Joined: 23 Jun 2009
Posts: 47

### Show Tags

21 Jul 2009, 22:49
Thanks! You are the absolute best.
Director
Joined: 03 Jun 2009
Posts: 757
Location: New Delhi
WE 1: 5.5 yrs in IT

### Show Tags

21 Jul 2009, 23:15
Another method is by substituting the options.
Tip: The numerical options in GMAT are sorted in increasing order.

Min Population = 10900
Population in other cities = (132000 - 10900) / 10 = 12110
Difference between min populated and other cities= 12110 - 10900 = 1211 ..(i)
10% of min population = 10% of 10900 = 1090 ..(ii)

As (i) is greater than (ii), hence invalid option.

Now try substituting option D (remember, now you don't need to substitute A or B, as these values are even smaller then C, and will lead to greater difference)
Min Population = 11000
Population in other cities = (132000 - 11000) / 10 = 12100
Difference between min populated and other cities= 12100 - 11000 = 1100 ..(i)
10% of min population = 10% of 11000= 1100 ..(ii)

As (i) is equal to (ii), hence valid option. Answer D.
_________________
Intern
Joined: 18 Jul 2009
Posts: 12

### Show Tags

21 Jul 2009, 23:27
bigoyal wrote:
Another method is by substituting the options.
Tip: The numerical options in GMAT are sorted in increasing order.

Min Population = 10900
Population in other cities = (132000 - 10900) / 10 = 12110
Difference between min populated and other cities= 12110 - 10900 = 1211 ..(i)
10% of min population = 10% of 10900 = 1090 ..(ii)

As (i) is greater than (ii), hence invalid option.

Now try substituting option D (remember, now you don't need to substitute A or B, as these values are even smaller then C, and will lead to greater difference)
Min Population = 11000
Population in other cities = (132000 - 11000) / 10 = 12100
Difference between min populated and other cities= 12100 - 11000 = 1100 ..(i)
10% of min population = 10% of 11000= 1100 ..(ii)

As (i) is equal to (ii), hence valid option. Answer D.

Nice explaination with PITA(plug in the answer tech)
I started off with the same bt shifted to my instincts :D

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: Please Crack the Math (PS) Question! Anyone! Thanks ;)   [#permalink] 21 Jul 2009, 23:27
Display posts from previous: Sort by

# Please Crack the Math (PS) Question! Anyone! Thanks ;)

Moderators: chetan2u, KarishmaB, niks18, Bunuel

# Events & Promotions

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.