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01 May 2018, 04:55
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
70% (02:35) correct
30%
(02:51)
wrong
based on 403
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Points A, B, C, and D are on the number line above, and \(AB = CD = \frac{1}{3}BC\) What is the coordinate of C ?
A. \(\frac{13}{30}\)
B. \(\frac{9}{20}\)
C. \(\frac{11}{24}\)
D. \(\frac{7}{15}\)
E. \(\frac{29}{60}\)
Attachment:
test.jpg [ 11.38 KiB | Viewed 38750 times ]
01 May 2018, 05:28
Kudos
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Bunuel
Points A, B, C, and D are on the number line above, and \(AB = CD = \frac{1}{3}BC\) What is the coordinate of C ?
A. \(\frac{13}{30}\)
B. \(\frac{9}{20}\)
C. \(\frac{11}{24}\)
D. \(\frac{7}{15}\)
E. \(\frac{29}{60}\)
Attachment:
test.jpg
Assume Length of AB = x
so AB = CD = x and BC = 3x
so distance between AD = \(5x = \frac{1}{3}-\frac{1}{2} = \frac{1}{6}\)
or \(x= \frac{1}{30}\)
now AC = \(4x+\frac{1}{3} = \frac{4}{30} + \frac{1}{3} = \frac{14}{30} or \frac{7}{15}\)
Hence Option D
General Discussion
18 May 2018, 01:34
Kudos
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Let B coordinate be x and C be y
So AB=CD=BC/3
x-(1/3)=(1/2)-y=(y-x)/3
x-(1/3)=(y-x)/3 --------(1)
(1/2)-y=(y-x)/3---------(2)
Two equations above
Compare and solve for y
y comes out to be 7/15
Posted from my mobile device
So AB=CD=BC/3
x-(1/3)=(1/2)-y=(y-x)/3
x-(1/3)=(y-x)/3 --------(1)
(1/2)-y=(y-x)/3---------(2)
Two equations above
Compare and solve for y
y comes out to be 7/15
Posted from my mobile device
