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23 Aug 2018, 04:12
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
92% (00:53) correct
8%
(01:44)
wrong
based on 45
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If the area of triangle ABC is 15, side AC has length 10, and segment BD is perpendicular to segment AC, what is the length of segment BD?
A. 9
B. 6
C. 5
D. 3
E. 1.5
Attachment:
image006.jpg [ 2.32 KiB | Viewed 1940 times ]
23 Aug 2018, 04:21
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Given: Area of triangle(ABC) = 15 | Length of side(AC) = 10
The perpendicular to the segment AC, BD is the height of the triangle.
Here, AC is the length of the base. Area = \(\frac{1}{2} * AC * BD = 15\).
Therefore, the length of the segment BD \(= \frac{15*2}{AC} = \frac{30}{10}\) = 3(Option D)
23 Aug 2018, 07:27
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Bunuel
\(\frac{1}{2}*AC*BD = 15\)
Or, \(10*BD = 30\)
Or, \(BD = 3\) , Answer must be (D)
