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Originally posted by skharkia on 14 May 2020, 10:40.
Last edited by skharkia on 14 May 2020, 10:59, edited 2 times in total.
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Any triangle in which the lengths of the sides are in the ratio 3:4:5 is a right triangle. In general, if a, b, and c are the lengths of the sides of a triangle and a^2 + b^2 = c^2, then the triangle is a right triangle.
In 30°− 60°− 90° triangles, the lengths of the sides are in the ratio 1:sqrt(3):2. For example, in ΔXYZ, if XZ = 3, then XY = 3*sqrt (3) and YZ = 6.
Can anyone explain how in 30-60-90, XY is coming as 3*sqrt(3) ?
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Any triangle in which the lengths of the sides are in the ratio 3:4:5 is a right triangle. In general, if a, b, and c are the lengths of the sides of a triangle and a^2 + b^2 = c^2, then the triangle is a right triangle.
In 30°− 60°− 90° triangles, the lengths of the sides are in the ratio 1:sqrt(3):2. For example, in ΔXYZ, if XZ = 3, then XY = 3*sqrt (3) and YZ = 6.
Can anyone explain how in 30-60-90, XY is coming as 3*sqrt(3) ?
Show more
30:60:90 -> 1:root 3: 2 -> a:a root3:2a, in ΔXYZ, if XZ = 3, then XY = 3*sqrt (3) and YZ = 6 Now as per above example, xz (30°)= 3 = a, XY (60°)= 3 root 3 =a root 3 and YZ (90°)= 6 = 2a. so, here a =3. Similarly, 45° - 45° - 90° triangle have side ratio as a:a:a root 2.
Any triangle in which the lengths of the sides are in the ratio 3:4:5 is a right triangle. In general, if a, b, and c are the lengths of the sides of a triangle and a^2 + b^2 = c^2, then the triangle is a right triangle.
In 30°− 60°− 90° triangles, the lengths of the sides are in the ratio 1:sqrt(3):2. For example, in ΔXYZ, if XZ = 3, then XY = 3*sqrt (3) and YZ = 6.
Can anyone explain how in 30-60-90, XY is coming as 3*sqrt(3) ?
Show more
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In 30°− 60°− 90° triangle, \(\frac{a}{sin(30)}= \frac{b}{sin60}= \frac{c}{sin90}\) \(2a= \frac{2b}{\sqrt{3}}= c\) \(2a= \frac{2b}{\sqrt{3}}= c\) \(a= \frac{b}{\sqrt{3}}= \frac{c}{2}\) ratio of sides a:b:c = \(a: a\sqrt{3}:2a\) = \(1: \sqrt{3}:2\)
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.