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13 Jun 2019, 00:34
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A class in a certain school consists of boys and girls in the ratio of 2:1. In a mathematics test, 60% of the class passed the test. If 40% of the boys failed the test, what percentage of the class are girls who passed the test?
A. 10%
B. 20%
C. 30%
D. 40%
E. 60%
A. 10%
B. 20%
C. 30%
D. 40%
E. 60%
13 Jun 2019, 06:08
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Assume 30 students in class. So boys 20 and girls 10.
60%passed so 18 students passed.
40% of boys failed. So 60% of boys = .6*20=12 passed the test.
Remaining 6 students who passed must be girls; so % is 6/30*100=20% IMO B.
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60%passed so 18 students passed.
40% of boys failed. So 60% of boys = .6*20=12 passed the test.
Remaining 6 students who passed must be girls; so % is 6/30*100=20% IMO B.
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13 Jun 2019, 07:47
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mangamma
The easiest way to solving this problem is by assuming a random number for the total
number of students in the class. Arvind42 has already demonstrated this.
If there are 3x students in the class and 40% of the boys failed the test, 60% or 0.6*2x = 1.2x pass.
We are told that 60% of the class passes the test -> 0.6*3x or 1.8x of the class passes the test. The
remaining 0.6x(1.8x - 1.2x) are girls who pass the test.
Therefore, the percentage of girls in the class who pass the test are \(\frac{0.6x}{3x}\) = 20%(Option B)
