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tobiastt
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GmatPrep - coordinate Geo 06 Dec 2006, 04:09
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Need help on this one - Thanks!



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Viperace
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GmatPrep - coordinate Geo 06 Dec 2006, 05:26
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First, u need to realize that angle between PO and horizontal axis is 30degree

From there, u can work out angle the other angle (OQ and horizontal axis), it is 60.
Then, notice that the hipotenus OQ is 2, because Q and P lies in the same circle.
WIth OQ and the angle, u got can get S.


Cant show the diagram.. lol
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sirishast
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GmatPrep - coordinate Geo 07 Dec 2006, 02:00
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See the attachment
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solution.doc [290.5 KiB]
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tobiastt
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GmatPrep - coordinate Geo 07 Dec 2006, 05:51
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thanks for the explanation sirishast
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MBAlad
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GmatPrep - coordinate Geo 07 Dec 2006, 16:39
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Alternative method:

Quote:
Shobhitb wrote:

My method:

if two line are perpendicular, product of slopes = -1

Therefore
((t-0)/(s-0))*((1-0)/(srt(3)-0)) = -1
t=s* sqrt(3) ------ A

Also distance of both points from origin is same

Sqrt(t^2 + s^2) = sqrt (3+1) = 2
t^2 + s^2 = 4 -----B

Solving both A & B

3*s^2 + s^2 = 4
s = +1 or -1 (corresponding to Q1 & Q3)

from diagram choose +1
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jainan24
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GmatPrep - coordinate Geo 07 Dec 2006, 17:52
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I think angle method is shorter than quadratic method and more prone to errors



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