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Problem Solving - Mixture

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Problem Solving - Mixture  [#permalink]

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New post 08 Aug 2009, 07:19
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A
B
C
D
E

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Question Stats:

50% (01:30) correct 50% (01:55) wrong based on 5 sessions

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5 litres of water is added to a certain quantity of pure milk costing $3 per litre. If, by selling the mixture at the same price as before a profit of 20% is made, what is the amount of pure milk in the mixture?

A. 25
B. 18
C. 20
D. 30
E. None of these

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Re: Problem Solving - Mixture  [#permalink]

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New post 08 Aug 2009, 07:55
Let the quantity of milk be x liters

Then, before adding water, x liters was sold at $3 per liters for the total price of $3x

Adding 5 liters of water brings the total volume to (x + 5) liters.
Therefore, at $3/liter, the total dollar value of the mixture becomes $3(x+5)

Now it's given that after adding the water there is a profit of 20%, therefore
20% increase in dollar value BEFORE adding water = dollar value AFTER adding water
1.2(3x) = 3(x+5)

solve for x to get a) 25
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Re: Problem Solving - Mixture  [#permalink]

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New post 08 Aug 2009, 20:51
OA A

3 rs/lit = 1.2 *[x (rs/lit)]

hence actual price = 2.5 rs /lit

hence 2.5/(3-2.5) = amount/5

amount = 25 lit
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Re: Problem Solving - Mixture  [#permalink]

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New post 11 Aug 2009, 11:10
1
Since the mixture is sold at the cost price of the pure milk.
Profit in this case is only the 5 lts of water added to the pure milk.
So inoreder to get 20% profit this 5 lit has to be 20% of pure milk. So its 25 lit of milk

A

/Prabu
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Re: Problem Solving - Mixture  [#permalink]

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New post 11 Aug 2009, 11:49
bhushan252 wrote:
OA A

3 rs/lit = 1.2 *[x (rs/lit)]

hence actual price = 2.5 rs /lit

hence 2.5/(3-2.5) = amount/5

amount = 25 lit


Bhushan,

Is the OA A or is that your answer?
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Re: Problem Solving - Mixture  [#permalink]

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New post 02 Oct 2017, 14:27
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Re: Problem Solving - Mixture &nbs [#permalink] 02 Oct 2017, 14:27
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