It is currently 22 Jun 2017, 19:05

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

ps

Author Message
Senior Manager
Joined: 30 Aug 2003
Posts: 322
Location: dallas , tx

Show Tags

10 Dec 2003, 11:16
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The weight of a glass jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fractional part of the beans remain in the jar?
1/12
1/3
2/5
1/2
2/3
_________________

shubhangi

Manager
Joined: 26 Aug 2003
Posts: 233
Location: United States

Show Tags

11 Dec 2003, 12:52
1/2?

j = weight of empty jar
b = weight of beans
A = weight of jar full of beans

A = j + b
A = j + 4j .... we're told weight of jar is 20% that of when it's full so b = 4j or 80% of the weight
A = 5j

After emptying some 60% left:

A = j + b
5j = j + b .... from above calculation
3j = j + b .... simply take 60% of 5
2j = b

This tells us half as many beans are left in the jar after emptying a little.
Director
Joined: 14 Oct 2003
Posts: 583
Location: On Vacation at My Crawford, Texas Ranch

Show Tags

11 Dec 2003, 13:38
Pick a number
100 = total weight of jar when filled with beans
Therefore, 20 = empty, 80 = weight of beans.

after beans removed = 60; therefore 40 is the weight of beans removed thus only half of the beans + plus the tare weight of the jar remains.

1/2
Senior Manager
Joined: 30 Aug 2003
Posts: 322
Location: dallas , tx

Show Tags

11 Dec 2003, 14:52
My method was same as titleist.. so 1/2 is correct...hope so.
coz answer to this question is also not given.
_________________

shubhangi

CEO
Joined: 15 Aug 2003
Posts: 3454

Show Tags

13 Dec 2003, 00:30
shubhangi wrote:
The weight of a glass jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fractional part of the beans remain in the jar?
1/12
1/3
2/5
1/2
2/3

Total weight = weight of coffee jar = 100
Weight of glass jar = 20
Weight of the coffee beans = 80... (100-20)...............(a)
Original total weight = 100
New weight = 60% * 100 = 60
New weight of the beans = 40 ( 60-20).............(b)
Fraction =40/80 =1/2

thanks
praetorian
SVP
Joined: 30 Oct 2003
Posts: 1790
Location: NewJersey USA

Show Tags

13 Jan 2004, 09:10
G = 0.2( G + C )
After some beans were removed C1 beans remained
so
G+C1 = 0.6(G+C)
C1 = 0.6(G+C) - G = 0.6(G+C) - 0.2(G+C) = 0.4(G+C)
so
C1/(G+C) = 0.4 = 2/5 ( I think this is what Geethu did )

But the question is asking C1/C
Since C = 4G
C1/C = 0.4 * 5 / 4 = 1/2
13 Jan 2004, 09:10
Display posts from previous: Sort by