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# Set A, B, and C consist of the following elements:

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Intern
Joined: 16 Jun 2011
Posts: 29
Set A, B, and C consist of the following elements:  [#permalink]

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06 Nov 2013, 11:26
2
1
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(N/A)

Question Stats:

67% (00:43) correct 33% (01:38) wrong based on 29 sessions

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Set A, B, and C consist of the following elements:
A {0, 3, 4, 2, 0, 4, 7, 8, 4, 17} B {20, 12, -7, -9, -5, -7, 11, -5, 68} C {-1.5, 0, 1.5}.

If Z is defined as the sum of modes of sets A, B, and C, what is the value of Z?
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Re: Set A, B, and C consist of the following elements:  [#permalink]

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06 Nov 2013, 11:45
My guess will be -2.

It's clear that the mode of A is 4.

I'm not entirely sure how to take the mode of B if there are two -5 and two -7. So I'll pretend it's -6.

The mode of C should be 0, as I know that a uniform distribution has the same mode, median and mean.

So 4+(-6)+0 = -2.

I hope someone else can enlighten me on this question.
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Re: Set A, B, and C consist of the following elements:  [#permalink]

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06 Nov 2013, 11:47
wastedyouth wrote:
Set A, B, and C consist of the following elements:
A {0, 3, 4, 2, 0, 4, 7, 8, 4, 17} B {20, 12, -7, -9, -5, -7, 11, -5, 68} C {-1.5, 0, 1.5}.

If Z is defined as the sum of modes of sets A, B, and C, what is the value of Z?

A mode is a number that has the highest frequency in a data set.
So in Set A.. 4 occurs maximum times... in B its -7 and -5..C has no mode...
so sum=+4-7-5=-8.
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Re: Set A, B, and C consist of the following elements:  [#permalink]

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10 Dec 2016, 23:31
1
I hope below solution helps :-

Mode of a set of numbers is the element in the set which occurs maximum number of times:

In set A, 4 is the mode.
In set B, both -7 and -5 are the modes (It is a bimodal set)
In set C, there is no mode.

Sum of the modes = 4 + (-5) + (-7) = -8.

Hope this is all right!
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Joined: 15 Feb 2018
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Re: Set A, B, and C consist of the following elements:  [#permalink]

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10 Apr 2018, 06:16
Mode for A: 4
Mode for B: -7 and -5
Mode for C:0
Thus sum is -8
Re: Set A, B, and C consist of the following elements:   [#permalink] 10 Apr 2018, 06:16
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